Cubic 3 of 2 times cubic - 2 of 6 + (- 50) times cubic 0 + (cubic - 2 of 9 times cubic 3 of 3) and then squared... Equal to?

Cubic 3 of 2 times cubic - 2 of 6 + (- 50) times cubic 0 + (cubic - 2 of 9 times cubic 3 of 3) and then squared... Equal to?

Cubic 3 of 2 times cubic - 2 of 6 + (- 50) times cubic 0 + (9 times cubic 3 of 3) and then square
=8*1/36+1+(1/3^4*3^3)^2
=2/9+1+(1/3)^2
=2/9+9/9+1/9
=12/9
=4/3

The speed ratio of the freight car to the passenger car is 5:6. After the two cars start, they meet at a distance of 4 km from the midpoint. What is the distance between them

The distance between Party A and Party B can be regarded as 11 (5 + 6), 5 for freight cars and 6 for passenger cars. The distance between the meeting point and the midpoint is 0.5 (11 / 2-5), and the distance between 0.5 and 4 km, so the distance between Party A and Party B is 88 km (4 / 0.5 * 11)
Countable formula: 4 / [(5 + 6) / 2-5] * 11 = 88 (km)
Good luck!

Given x ＜ - 2, find the maximum value of function y = 2x + 1 / (x + 2)

x+20
Then y = 2x + 4 + 1 / (x + 2) - 4
=-2a-1/a-4
=-(2a+1/a)-4
a>0
2a+1/a>=2√(2a*1/a)=2√2
-(2a+1/a)

A pile of soil, if it takes 30 days to transport 360 vehicles a day, now it needs to complete the task five days in advance, how many vehicles a day?

Suppose x cars are transported every day, (30-5) x = 360 × 30, the solution is x = 432

The volume of a cone is 6.28 cubic meters, the bottom area is 13.56 square decimeters, and its height is () DM

6.28*100/(1/3*12.56)=150dm
The ground should be 12.56. Is it wrong

It can be divided by 25 and 60. The maximum number should be

25 = 5 × 5, 60 = 5 × 12, the maximum number should be 5

If (a + 2b) (a-b) = 0, what is the value of 3A + B / 3a-b?
Please make it clear~
1. If (a + 2b) (a-b) = 0, then the value of 3A + B / 3a-b is?
2. When the triangle ABC paper is folded along the de, when point a falls inside the quadrilateral BCDE, there is a quantitative relationship between angle A and angle 1 plus angle 2
Explore the relationship and write the reasons

"Thumb, index finger, middle finger, ring finger, little finger", how to read, to voice!

Thumb (Samu) index finger first finger (finger GE) middle finger ring finger, forth finger little finger

If x and Y belong to R, and 3x ^ + 2Y ^ = 6, then the maximum value of X + y is, and the minimum value of x ^ + y ^ is

Using parametric equation to solve the optimal solution~
Or construct auxiliary functions
3x＾2＋2y＾2＝6
y^2=(6-3x^2)/2
t=x^2+y^2
=x^2+(6-3x^2)/2
=x^2+3-3x^2/2
=-x^2/2+3.
It is easy to know that when x = 0, t has a maximum value of T = 3
When 3x ^ 2 = 6, that is, x ^ 2 = 2, there is a minimum value, t = - 2 / 2 + 3 = - 1 + 3 = 2

-1.7. - 13.19. General term formula

a1=-1
an=(-1)^n*[6n -5]