The simplest way that the square of x minus 8x plus 16 equals 1... I'm going to take steps

The simplest way that the square of x minus 8x plus 16 equals 1... I'm going to take steps

X2-8x + 16 = (x-4) square, then x-4 equals one or minus one, and finally x is 5 or 3

How to calculate the square of X - 8x + 16 = 0
There are two real roots

x²-8x+16=0
(x-4)²=0
x=4
When △ = B & sup2; - 4ac = 64-4 * 64 = 0
This equation has two equal real roots

The size of each group (1) was negative 8 / 4, negative 9 / 10 (2) was negative 0.618, negative 3 / 5 (3) was 0, | negative 8|

1. Nine out of ten
2. Minus three fifths
3. The absolute value of negative eight is 8, so / negative eight / big

Several simple English multiple choice questions and fill in the blanks
1.Nothing is difficult in the world if you set your m__ To do it
2.-Would you mind watering the flowers for me?
-( ).I have to go to the post office.
A.Not at all B.Never mind
C.No,please D.Sorry,I can't
3.We ( )talking until late into the night and enjoyed ourselves.
A.went on B.put on C.help on D.bagan on
Each question can be followed by a note,

mind
D
A

As shown in the figure, in rectangle ABCD, ab = 12, ad = 10, fold the rectangle so that point B falls at the midpoint E on the edge of AD, then crease FG=______ ．

Let GH ⊥ AB, perpendicular to h, connect EF, eg, GB. According to the properties of folding, FB = ef (set as x), eg = GB, then AF = 12-x, and AE = 12ad = 5 when B falls at the midpoint e of AD. in RT △ AEF, AE2 + af2 = ef2, that is 52 + (12-x) 2 = X2, the solution is x = 16924. Let CG = y, then DG = 12-y, in RT △ BCG and RT △ DEG, BG = eg, BC2 + CG2 = DG2 + de2 That is: 102 + y2 = (12-y) 2 + 52, the solution is y = 6924, ｜ FH = fb-bh = fb-cg = X-Y = 256, in RT △ FGH, FG = FH2 + GH2 = (256) 2 + 102 = 656

Simple calculation of 32 * 125 * 25

32*125*25=4*8*125*25=100*8*125=100*4*2*125=400*250=100000

Why can simple higher order inequalities be solved into several different factors?

As chkdsk11 said, I don't know your mathematical level. If you have learned advanced numbers, just follow chkdsk11. If you can't understand it, just follow what I said. However, this statement is not professional. Let's analyze a polynomial such as (x ^ A + x ^ b) (x ^ C + x ^ D) (x ^ e + x ^ f) (...) ）For him, we go to get

In rectangular ABCD, ah = HB = 4, AE = 1 / 2DE = 4, DG = 3, BF = FC = 6, what is the area of quadrilateral hfge

∵AE=AH=4
5 × 4 × 4 = 8
∵DE=2AE=8,DG=4
5 × 8 × 4 = 16
∵FC=6,CG=4
5 × 6 × 4 = 12
∵HB=4,BF=6
5 × 4 × 6 = 12
The area of rectangle ABCD = ab × BC = (ah + HB) × (BF + FC) = (4 + 4) × (6 + 6) = 96
Area of quadrangle hfge = area of rectangle ABCD - △ area of AEH - △ area of EDG - △ area of GCF - △ area of HbF = 96-8-12-16-12 = 48

The long march rocket developed by Chinese space scientists is used to send the satellite into space. The shell of the rocket must be made of high hardness and high melting point material. Please explain why this material must be used

When a rocket transports a satellite spacecraft into space, it needs to pass through the atmosphere. If it wants to reach the first space speed at high speed, the high speed will cause friction between the rocket shell and the atmosphere. Friction will generate heat, and the heat is very large in that case. Therefore, it is necessary to use high melting point and high hardness materials (titanium alloy) and apply a layer of material on the surface of the rocket (or re-entry capsule), By liquefying and vaporizing the protective material at high temperature, the surface temperature of the rocket (or re - entry capsule) can be reduced

Intelligence calculation
There are 63 students who take part in type a examination, 89 students who take part in type B examination, and 47 students who take part in type C examination. Among them, 46 students take part in two kinds of examinations at the same time, 24 students take part in three kinds of examinations at the same time, and 15 students do not take any examinations. How many students are there in this school?
If you know how to answer, please write down the detailed steps of calculation,

First count the total number of examination: 63 + 89 + 47 = 199
Minus two exams, the number of people taking three exams: 199-46 * 2-24 * 3 = 35
This 35 is the number of people who have only one test, that is, the number of people who have one test is 35
There are only three tests in total, so:
The total number of people = no test + one test + two test + three test = 46 + 24 + 15 + 35 = 120