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(x-3) ^ 2 = (3x-2) ^ 2 factorization solution equation
(3X-2)^2-(x-3)^2=0
[(3X-2)+(X-3)][(3X-2)-(X-3)]=0
(4X-5)(2X+1)=0
I hope I can help you,
A mathematical problem, recursive equation calculation, must use a simple method. 6.66 * 2.22 + 5.56 * 3.33
6.66*2.22+5.56*3.33
=3.33*2*2.22+5.56*3.33
=3.33*（4.44+5.56）
=3.33*10
=33.3
If n is any integer, the value of (n + 11) 2-n2 can always be divided by K, then K is equal to the multiple of () a.11 b.22 c.11 or 12d.11
Why can't it be a multiple of 11
（n+11）2-n2
=(n+11+n)(n+11-n)
=11*(2n+11)
If n is any integer, the value of (n + 11) 2-n2 can always be divided by K, then K is equal to (a.11)
Solution equation: x = 3x = 0.16
x-3x=0.16
-2x=0.16
x=-0.08
12.8-0.5 × 0.5-0.75 is equal to? Calculated by a simple method
12.8-0.5×0.5-0.75
=12.8-0.25-0.75
=12.8-（0.25+0.75）
=12.8-1
=11.8
Given the sequence an = 1 / [n (n + 1) (n + 2)], find the limit of Sn
An=1/2*[1/n(n+1)-1/(n+1)(n+2)]
Sn=1/2*[1/2-\1/6+1/6-1/12+.+1/n(n+1)-1/(n+1)(n+2)]
=1/2*[1/2-1/(n+1)(n+2)]
What is the remainder of 1992 divided by 7
If 100010001 is divisible by 7, then three 1992 connected numbers [199219921992] can be divisible by 7. Because 1992 △ 3 = 664, then every three 1992 segments, the original number 19921992 1992= 199219921992000…… 000 + 199219921992000…… 000 + …… + 19921992199200000000...
How to calculate 80.8 times 1.25 with simple calculation
80.8 times 1.25
＝（80＋0.8）×1.25
＝80×1.25＋0.8×1.25
＝100＋1
＝101
Find the general solution of the differential equation y "- 4Y = - 2x,
First, find the general solution of Y '' - 4Y = 0, the characteristic equation of Y '' - 4Y = 0: R ^ 2-4r = 0
The eigenvalues are: 0,4
The corresponding items are: C1, C2 * e ^ 2x
The general solution of the differential equation y "- 4Y = 0 corresponding to the characteristic equation is obtained
：C1+C2*e^2x
A special x * QX * e ^ 0 of Y "- 4Y = - 2x = = 2x
Qx=2
The general solution of Y "- 4Y = - 2x is: C1 + C2 * e ^ 2x + 2
If a is not equal to B, then the solution set of inequality (x-a ^ 2-B ^ 2) (2ab-x) about x greater than or equal to 0 is
(x-a^2-b^2)(2ab-x)>=0
x>=a^2+b^2,x2ab,
So the solution set is
2ab
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