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If point m is a point on Y-axis and △ ABM is a right triangle, then the coordinates of point m are
Let m (0, b)
AM²=1+b²
AB²=5
BM²=9+(b+1)²
There are three cases
1、AM²=AB²+BM²
1+b²=5+9+b²+2b+1
∴b=-7
2、AB²=AM²+BM²
5=1+b²+9+b²+2b+1
2b²+2b+6=0
unsolvable
3、BM²=AM²+AB²
9+b²+2b+1=5+1+b²
2b=-4
∴b=-2
The coordinates of point m are (0. - 7) or (0, - 2)
The focal coordinates of the first-order function y = 3x-4 and the first-order function y = 2x / 3 + 2 / 3 are processes
Let y be equal to 3x-4 = 2 / 3x + 3, then x = 3
Y = 5 can be obtained by taking x = 3 into y = 3x-4 or y = 2 / 3x + 3
Focus coordinates (3,5)
Using the image of the first-order function to solve the binary first-order equations 3x + 5Y = 8,2x-y = 1 (to draw the image of the first-order function)
It is converted to y = - 3 / 5x-8 / 5 and y = 2x-1
Draw two straight lines to see the coordinates of the intersection
It's the solution of the system of equations
Given X / 2 = Y / 3 = Z / 4, then the value of (x ^ 2-2y ^ 2 + 3Z ^ 2) / XY + 2yz + 3zx is
Let X / 2 = Y / 3 = Z / 4 = K
Then: x = 2K; y = 3K; Z = 4K
(x^2-2y^2+3z^2)/xy+2yz+3zx
=(4k²-18k²+48k²)/(6k²+24k²+24k²)
=34/54
=17/27
One quarter of the boys in a school are 50 more than one third of the girls. Three quarters of the boys are twice as many as the girls
Suppose male x female y
therefore
1/4*x-1/3*y=50
3/4*x=2y
The results of solving the above two equations are as follows
x = 400,y = 150
When k = (), the polynomial-x ^ 2 + 2kxy-4y ^ 2 + xy-5x-1 contains no XY term
-x^2+2kxy-4y^2+xy-5x-1
=-x^2+(2k+1)xy-4y^2-5x-1
Without XY, you must:
2k+1=0
k=-1/2
The number of boys in Grade 6 is 80% of the number of girls, and the number of girls is ()% of the number of boys
Boys are 80% of girls, that is
Boys divided by girls is 80%
Girls are unit one, boys are 80%
How much is the unit equivalent to 80%?
100%÷80%=125%
So girls are 125% of boys
Is ± √ 0.04 equal to the square root of 0.04?
Yes, 0.04 is the arithmetic square root of 0.04
The sum of the three numbers of a, B and C is 70. The number of a is more than 2 times that of B. the number of C is less than 4 times that of B. the numbers of a, B and C are () () ()
Suppose a is x, B is y, C is Z
From the title
1、 X+Y+Z=70
2、 2Y+2=x
3、 3Y-4=Z
Take formula 2 and 3 into Formula 1 to get 2Y + 2 + y + 3y-4 = 70
Y=12
The rest is up to you
All integers are greater than 0, and all negative numbers are less than 0,
5% = ()% fill in the appropriate score
Integers include positive and negative integers. It is wrong for integers to be greater than 0
It's right that negative numbers are less than 0
eighty-five
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