Fixed point of power function Y = x squared Y = x cube The (- 1) power of y = x Y = 0 power of X The (1 / 2) power of y = x

Total constant over (1,1)

Sum function of power function ∑ (x * n) / N?

First of all, your n has no range. Second, is that the nth power of X? If so, and n goes from 0 to infinity, this is a very basic expansion of e ^ X. you can turn to the Taylor formula to see this expansion

Induction of power function
Y = x, the square of y = x, the third power of y = x, the half power of y = x, the common points of y = X-1 are crossing points. Please explain why

Obviously (1,1)

13 questions on page 4 and 10 questions on page 6 in Volume 2 of junior high school mathematics published by people's Education Press
I really can't think of it. It's better to write down the process of asking for advice. (the added value is not necessarily.)
13. The intersection point of line AB and ray OC is O, OD bisects BOC, OE bisects AOC. Try to judge the position relationship between od and OE.
10. In △ ABC, ad vertical BC, be vertical AC, ad = 6, be = 10, find the value of BC: AC

13. ∵ AB is a straight line and O is a point on ab
∴∠AOB＝180°
∵∠AOB＝∠AOC＋∠BOC
∴∠DOE＝1/2（∠AOC＋∠BOC）＝1/2∠AOB＝1/2×180°＝90°
That is OD ⊥ OE
10.∵AD×BC＝BE×AC＝2S△ABC
Ad = 6, be = 10
∴6BC＝10AC
That is 3bC = 5AC
∴BC:AC＝1/3:1/5＝5:3

As shown in the figure, in the parallelogram ABCD, e and F are the points on the extension line of Ba and CD respectively, and be = DF, AF intersects BC with H, CE intersects ad with G
As shown in the figure, in the parallelogram ABCD, e and F are the points on the extension line of Ba and CD respectively, and be = DF, AF intersects BC with H, CE intersects ad with G.
Verification: eg = HF.

`Because be = DF
And because ABCD is a parallelogram
So EA = CF
And because AB / / DC (parallelogram)
So EA / / CF
So EAFC is a parallelogram (a set of opposite sides are parallel and equal)
Because EAFC is a parallelogram,
So angle e equals angle F
And because angle bad = angle BCD,
So angle EAG = angle FCH
So triangle EAG is equal to triangle FCH (ASA)
So eg = HF
Since there are no simple symbol keys on the keyboard, please understand them slowly. Then review the problem-solving process in your mind, so that you will understand

Find the law - 10, - 7, - 4, (), (), 5

-10,-7,-4,（ -1）,（2 ）,5
The latter is three times more than the former

How can you be so _______ and still call yourself my friend?（kind）

Unkind, unkind
How can you be so ruthless and call yourself my friend?

Fold the square ABCD so that the vertex a coincides with the point m on the edge of CD, the crease intersects ad with E, BC with F, and the edge AB with BC intersects with G (as shown in Figure 4)
If the side length of the square is 2 and M is the midpoint of CD, find the length of EM

EM = AE, CM = DM = 1
Let em = x, so AE = x, de = 2 - X
Triangle DEM is a right triangle, so EM * EM = de * de + DM * DM
So x * x = 1 * 1 + (2 - x) * (2 - x)
So x = 1.25

Simple calculation: 99000 / 25 / 4 0.125 * 32 * 2.5 111 * 99 * 111

99000/25/4=99000÷（25×4）=99000÷100=990 0.125*32*2.5=（0.125×8）×（0.4×2.5）=1×1=1 111*99*111=（111×111）×（100-1）=12321×（100-1）=1232100-12321=1219779

Which is more reasonable, the arithmetic average or the weighted average?
Example: A and B are divided into three factors: A, B and C, a 50 and B 30, 100 in total
a. B two people rate two things
Arithmetic mean: a = (AA + Ba + AB + BB + AC + BC) / 2
Weighted average method: a = AA * 0.5 + AB * 0.3 + AC * 0.2 + Ba * 0.5 + BB * 0.3 + BC * 0.2
Which is more reasonable?
Only the arithmetic average method is used to get the number of a and B, and the ranking. Is it different from the weighted average method?

The weighted average method is more reasonable,
Because in real life, the influence of each factor is not the same, it should be considered
Two methods of ranking will be different, you can choose some data, specific calculation to understand
The same result is only a special case

Fixed point of power function Y = x squared Y = x cube The (- 1) power of y = x Y = 0 power of X The (1 / 2) power of y = x