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Derivative function of F (x) = 3x-2 / x + 3 I totally forget that I am f (x) = 3-11 / x + 3 = 11 / (x + 3) * 2
f(x)=3x-2/x+3
f'(x)=3+2/x^2
Given the function FX = 1 / 3x ^ 3-ax + B, where real numbers a and B are constants
Let the derivative of y = f (x) be f '(x). Then when a = 1, for any x 1 ∈ [0,2], there always exists x 2 ∈ [0,2], such that f (x 1) = f' (x 2), and the value range of real number B is obtained
fx=1/3x^3-ax+b
When a = 1, FX = 1 / 3x ^ 3-x + B
f'x=x^2-1
Let f 'x > 0 get x > 1 or X
It is known that the function f (x) = 13x3 − AX2 + B has an extreme value at x = 2. (1) find the monotone interval of F (x); (2) if f (x) has and only has one zero point on R, find the value range of B
（1）f′（x）=x2-2ax… From the meaning of the question: F '(2) = 4-4a = 0, a = 1 (3) f ′ (x) = x2-2x, if f ′ (x) > 0, then x ＞ 2 or X ＜ 0 (5 points) Let f '(x) < 0, get 0 < x < 2 The monotone increasing intervals of (6 points) f (x) are (- ∞, 0) and
If the function y = - 4 / 3x ^ 2 + ax has three monotone intervals, then the value range of a is
Wrong
It is y = - 4 / 3x & sup3; + ax
y'=-4x²+a
There are three monotone intervals
That is, increase or decrease, increase or decrease
So the sign of Y 'is + - + or-+-
So there are two intersections of the Y 'and X axes
So the discriminant = 0 + 16A > 0
a>0
12 and 30 factorization prime factor, in seeking the maximum common factor
12=2*2*3
30=2*3*5
gcd(12,30)=2*3=6.
In the original algorithm of rational number, add the following new operation symbol "△"; when a > b, a △ B = 2B; when a ≤ B, a △ B = 3A
Then when x = 4, the value of (3 △ x) * x - (5 △ x) is (". And" - "are still multiplication and subtraction signs in rational number operation)
(3△x)*x-(5△x)
=(3△4)*4-(5△4)
=9*4-2*4
=36-8
=28
Draw a line segment equal to the known line segment a, you can use a compass in the_____________
Urgent need
One end of a given line segment is fixed, and the other end intercepts the given line segment. Then draw a circle. The distance from any point of the circle to the center of the circle is the length of the original line segment
If x + y ^ 2 + 1 is less than or equal to 2x + 2Y, find the value of X + y
Answer quickly
x^2+y^2+1
It is known that the three sides of a triangle are 15, 19 and 23 respectively. If the three sides of a triangle are shortened by X to form an obtuse triangle, the value range of X is obtained
Three sides a, B and C of obtuse triangle satisfy a ^ 2 + B ^ 2 < C ^ 2, where C is the largest side
The three sides are 15-x, 19-x and 23-x, of which 23-x is the largest side
That is to meet
（15-x)^2 + (19-x)^2 < (23-x)^2
Unfold and organize, get
x^2 - 22x + 57 > 0
That is, (x-3) (X-19) > 0
That is, x > 19 or x0
And because the three sides are still greater than 0 after shortening, it is necessary to omit x > 19
So to sum up,
0
We know that the quadratic function f (x) = AX2 + BX + C (ABC belongs to R) satisfies that when x = - 1, the function value is equal to 0, 1 is equal to 1, and for any real number, f (x) - x is greater than or equal to 0?
According to the meaning of the title,
F(-1)=a-b+c=0 (1),
F(1)=a+b+c=1 (2),
According to (2), B-1 = - a-c (3)
And f (x) - x = ax ^ 2 + (B-1) x + C > = 0 is r constant for X,
So a > 0 and delta = (B-1) ^ 2-4ac = 0 are constant and delta = (B-1) ^ 2-4ac is constant
RELATED INFORMATIONS
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