X-20:17 X: 5:4 = 15:2 to find the unknown x

X-20:17 X: 5:4 = 15:2 to find the unknown x

(x-17/20x)：4/5=15：2
(x-17/20x)×2=4/5×15
3/10x=12
x=12÷3/10
x=40

Find the unknown X; 4 to x = 1 / 6

4:x=1/6
x=4×6
x=24

A batch of goods was distributed to Party A and Party B according to the ratio of 5:3. Party a completed 4 / 5 of its task, and the rest was transported to Party B. Party B transported 480 tons in total
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How many tons are the goods altogether

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When m is a positive integer, the solution of the equation x-half of x-m is equal to two-thirds of X, which is nonnegative
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x-(x-m)/2=(2-x)/3
x=(4-3m)/5
The solution is nonnegative
4-3m>=0
m

Three fourths of a pile of stones are transported away, and five eighths of a ton are left. How many tons are there in total?

The remaining five eighths of a ton is one fourth of the total, multiplied by four to make a total of five fifths of a ton

Given that the line L and the line 3x-4y + 5 = 0 are symmetric about X axis, the equation of line L is solved
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The straight line 3x-4y + 5 = 0 intersects the x-axis and y-axis at two points a (- 5 / 3,0) and B (0,5 / 4), respectively,
Then the line l must pass through two points a and C (0, - 5 / 4) (C is the symmetric point of B about X axis),
The linear equation of l can be obtained from a and C coordinates
y=－﹙3／4﹚x－5／4,
That is: 3x + 4Y + 5 = 0

There are 64 people in the first workshop and 56 people in the second workshop of a factory. Now, due to work needs, the number of people in the first workshop is half of that in the second workshop. How many people need to be transferred from the first workshop to the second workshop?

Suppose you need to transfer x people from the first workshop to the second workshop, according to the meaning of the question: 2 (64-x) = 56 + X, the solution is x = 24; answer: you need to transfer 24 people from the first workshop to the second workshop

Given that 2 / 2 x = 3 / N = 4 / Z, find XY + 2yz + 3xz X & sup2; - 2Y & sup2; + 3Z & sup2;
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If it's Y: X / 2 = Y / 3; X = 2Y / 3; Y / 3 = Z / 4; Z = 4Y / 3; XY + 2yz + 3xz = (2Y / 3) y + 2Y (4Y / 3) + 3 (2Y / 3) (4Y / 3) = 6y & sup2; X & sup2; - 2Y & sup2; + 3Z & sup2; = (2Y / 3) & sup2; - 2Y & sup2; + 3 (4Y / 3) & sup2; = 34y & sup2

There are 54 students in class 51, of whom the boys are 20% less than the girls

Solution: let's set the female student as X person. If the male student is 20% less than the female student, then the male student is (x-20%). X + (x-20%) = 54, x = 30, male student: 54-30 = 24

x+y=6 xy=-3 x^2y+xy^2=?

x^2y+xy^2
=xy(x+y)
=-3*6
=-18