① Given f (2x) = 2x + 3, find f (x) 2. Given g (x) = 1-2x, f [g (x)] = 1-x & # 178; / X & # 178;, find the value of F (1 / 2)

① Given f (2x) = 2x + 3, find f (x) 2. Given g (x) = 1-2x, f [g (x)] = 1-x & # 178; / X & # 178;, find the value of F (1 / 2)

If G (x) = 1-2x, f [g (x)] = (1-x ^ 2) / x ^ 2, then f (1 / 2) is f [g (x)] = (1-x ^ 2) / x ^ 2, let g (x) = 1 / 2, 1-2x = 1 / 2, 2x = 1 / 2, x = 1 / 4, f (1 / 2) = (1 - (1 / 4) ^ 2) / (1 / 4) ^ 2

Given x ^ 2 + 2x + 1 + y ^ 2 minus 8y + 16 = 0, find the value of Y in X

(x+1)²+(y-4)²=0
∴x+1=0
y-4=0
∴x=-1
y=4
∴y/x=-4

If x and y satisfy the radical X-Y-Z + (2x-3x-5) &# 178; = 0, we can find the value of x-8y

From the meaning of the title: x-2y-3 = 0, 2x-3y-5 = 0, x = 1, y = - 1
The square root of x-8y = 3

1) Programming, output 100-999 between all the "narcissus number." narcissus number "is a three digit number, the number of its cube is equal to the number
Body. C language

void main()
{
int n = 100;
int a;
int b;
int c;
for( n=100;n<=999;n++)
{
a = n/100;
b = n/10%10;
c = n%10;
if ( n==(a*a*a+b*b*b+c*c*c))
{
printf("%d %d %d\n",a,b,c);
}
}
}

The distance between a and B is 240 km. The passenger cars and freight cars start from a and B and run in opposite directions. They meet in three hours. The speed of the passenger cars is 3 / 5 of that of the freight cars

If the speed of freight car is x, the speed of passenger car is 3 / 5x
3(x+3/5x)=240
8/5x=80
x=50
The speed of passenger car is 30 km / h and that of freight car is 50 km / h

The maximum value of 1-x square of function y = x is -
The minimum value of the function y = x times e to the negative x power X belonging to [0,4] is -

First: obviously, the problem of derivative is solved by Y '= 0
y'=√(1-x^2)-x^2/[√(1-x^2)]=0
We get x = (√ 2) / 2 (other solutions are removed)
Substituting into the original formula, y (max) = 1 / 2
Second:
Y '= (1-x) e ^ (- x)
When x > 1, y '

A pile of soil, if it takes 30 days to transport 360 vehicles a day, now it needs to complete the task five days in advance, how many vehicles a day?

Suppose x cars are transported every day, (30-5) x = 360 × 30, the solution is x = 432

If the height of a cylinder is increased by 2 decimeters, the side area will be increased by 12.56 square decimeters. The bottom radius of the cylinder is () decimeters

Bottom perimeter = 12.56 △ 2 = 6.28 decimeters
Radius = 6.28 △ 3.4 △ 2 = 1 decimeter
If you understand and solve your problem,

There are five non-zero natural numbers a, B, C, D, e. it is known that a minus B is greater than zero, AB is less than zero, ABC is greater than zero, CD is greater than zero, De is greater than zero
Judge the positive and negative of five rational numbers

Because A-B > 0, Ab0, B0, so C0, so, d0, so e

If the solution set of the system of inequalities 2x-m1 is - 1

2x-m1+2n (2+m)/2=1 m=0 1+2n=-1 n=-1