If the function f (x) defined on R is symmetric about x = A and about point (B, 0), and a is not equal to B, the period of function f (x) is obtained

If the function f (x) defined on R is symmetric about x = A and about point (B, 0), and a is not equal to B, the period of function f (x) is obtained


2 Ib-aI



The graph of the function f (x) defined on R is symmetric with respect to points a (a, b), B (C, b) (where C is not equal to a), and the period of F (x) is calculated?
T=2|a-c|


T=|a-c|



1. The general term formula of sequence an is an = n + B / N. if an ≥ A5 for any n ∈ n *, then the value range of real number B is?
2. The image of the odd function f (x) with the domain R is symmetric with respect to the line x = 1. When x belongs to [0.1], f (x) = x and the equation f (x) = log2013x (2013 is the subscript), the number of real roots is a.1006 b.1007 c.2012 d.2014
3. Given that the image of function f (x) is symmetric about point a (0,1) with respect to h (x) = x + 1 / x + 2, find the analytic expression of F (x)


First of all, the value of B must be positive, because when B is negative, the minimum value of an should be obtained at n = 1, so it is contradictory to the meaning of the topic, so it is directly A5



Find the unknown x (30-x) 2 + 4x = 84


x=12



It is known that the definition field of function f (x) is constant on R and satisfies the following conditions: F (x2-x1) = f (x2) - f (x1) + 1, f (x) - 1, f (x) + 1


0&2



Which of the functions y = sin2x and y = cos2x is a decreasing function on (π / 2, π)
Please explain the process


y=cos2x
It is suggested that you draw directly for easy understanding



If the length of one side of the rectangle is root 7 and the length of the diagonal is 4, the area of the shape is known


Let the other side be X. from the Pythagorean theorem, we get that,
x²+(√7)²=4²
The solution is x = 3
So the area of the rectangle is √ 7x = 3 √ 7



Known: x 2 + XY + y = 14, y 2 + XY + x = 28, find the value of X + y


∵ x2 + XY + y = 14 (1), Y2 + XY + x = 28 (2), ∵ ① + 2, we get: x2 + 2XY + Y2 + X + y = 42, ∵ (x + y) 2 + (x + y) - 42 = 0, ∵ (x + y + 7) (x + y-6) = 0, ∵ x + y + 7 = 0 or x + y-6 = 0, the solution is: x + y = - 7 or x + y = 6



19 * (2x + 5.2) = 201.4


19*(2x+5.2)=201.4
2x+5.2=201.4/19=10.6
2x=10.6-5.2=5.4
x=2.7



If the slopes of the straight lines of the inscribed parallelogram ABCD of ellipse X & # 178 / 16 + Y & # 178 / 9 = 1 all exist, then the product of the slopes of the straight lines AB and CD is?


Special value method
Taking the four vertices of the ellipse as the four vertices of the parallelogram just meets the meaning of the problem
A(-4,0),B(0,-3),C(4,0),D(0,3)
K(AB)=-3/4,K(CD)=-3/4
So the product of the slope of line AB and CD is 9 / 16