If the x power of function FX = (x power of 4-b) / 2 is odd, then B=

If the x power of function FX = (x power of 4-b) / 2 is odd, then B=


F (x) is an odd function,
So f (0) = (4 ^ 0-B) / 2 ^ 0
=(1-b)/1
=0
figure out
b=1
If you still have doubts, please ask



FX = 3ax + 1-2a has x0 on [- 1,1], such that fX0 = 0 (x0 ≠ plus or minus one) can find the value range of real number a


f(x0)=3aX0+1-2a=0
x0=(2a-1)/3a
And there exists x0 on [- 1,1]
So - 1



For the function f (x), if there exists x0 ∈ r such that f (x) = x0 holds, then x0 is called the fixed point of the function, and f (x) = (AX + b) / X is known
Find: (1) if f (x) has two fixed points - 2,3, find the zero point of function y = f (x);
(2) If a = 1, the function f (x) has no fixed point, find the value range of real number B?


The third sentence is "make f (x0) = x0". This is a new type of question to put forward a new concept and to investigate the ability of innovation and understanding. The college entrance examination must take the test. (1) - 2,3 is the fixed point, then f (- 2) = - 2, f (3) = 3, the solution is a = 1, B = 6F (x) = (x + 6) / X. the zero point of F (x) is 0, - 6. (2) a = 1, f (x) has no fixed point



100 ° - 36 ° 18 minutes 52 seconds
What's the equivalent?


100 degrees - 36 degrees 18 minutes 52 seconds
=99 degrees 59 minutes 60 seconds - 36 degrees 18 minutes 52 seconds
=(99-36) degrees (59-18) minutes (60-52) seconds
=63 degrees 41 minutes 8 seconds



The limit of X * sin (1 / x) when x tends to positive infinity


Original formula = sin (1 / x) / (1 / x)
Obviously, 1 / X tends to zero
So limit = 1



Simple calculation of 8.93-2 and 7 of 11 - (1 and 1 of 11 times 4 of 23 + 4 of 23)
If you answer well, you will get extra points!





If cos ^ 2 (x / 2) = SiNx, then TaNx / 2 is equal to


cos^2(x/2)=sinx
cos^2(x/2)=2sinx/2cosx/2
cosx/2(cosx/2-2sinx/2)=0
Cosx / 2 is not 0
cosx/2-2sinx/2=0
tanx/2=1/2



72 * 81 + 10.4 calculated by a simple method


72*81+10.4
=72*(80+1)+10.4
=72*80+72+10.4
=5660+82.4
= 5842.4



Through the point m (2,1), make a straight line intersection hyperbola x2-y2 = 1 at two points a and B. if the point m is the midpoint of line AB, find the equation of line ab


Answer: let the straight line be Y-1 = K (X-2), y = kx-2k-2k + 1 to enter hyperbolhyperbola x \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\i'm sorry



To solve the equation, 1 / 3 X-1 / 4 x = 10 3x-1 / 4 x = 7 / 8 X-60% x = 100


1/3x-1/4x=10
1/12x=10
x=10÷1/12
x=120
3x-1/4=7/8
3x=7/8+1/4
3x=9/8
x=9/8÷3
x=3/8
x-60%x=100
40%x=100
x=100÷40%
x=250
Remember to write the explanation, I hope you can master the method