Let min {x, y} denote the minimum value of X and y, for example, min {0,2} = 0, min {12,8} = 8, then the function y of X Let min {x, y} denote the minimum value of X and y, for example, min {0,2} = 0, min {12,8} = 8, then the function y of X can be expressed as ()

Let min {x, y} denote the minimum value of X and y, for example, min {0,2} = 0, min {12,8} = 8, then the function y of X Let min {x, y} denote the minimum value of X and y, for example, min {0,2} = 0, min {12,8} = 8, then the function y of X can be expressed as ()


From 2x ≥ x + 2 we get x ≥ 2 so min {2x, x + 2} = x + 2 so y = x + 2 (x ≥ 2)
From 2x < x + 2, we get x < 2 so min {2x, x + 2} = 2x so y = 2x (x < 2) y = min {2x, x + 2} (in fact, when x takes what value, y = x + 2 or 2x)



Min {a, B} is used to represent the minimum value of a and B. if f (x) = min {5-2 | x | x2-2x}, then the maximum value of F (x) is______ .


From the equation 5-2 | x | = x2-2x, the left intersection coordinate is (- 1,3). Draw the image of this function, as shown in the figure. It can be seen from the figure that when x = - 1, the maximum value of F (x) is 3. So the answer is: 3



Given that the solution set of inequality AX2 + BX + C > 0 is (α, β), and 0 < α < β, the solution set of inequality CX2 BX + a > 0 is obtained


The solution set of the inequality AX2 + BX + C > 0 is (α, β). α, β are the two real roots of the quadratic equation AX2 + BX + C = 0, and a < 0. The inequality CX2 BX + a > 0 is reduced to cax2 − Bax + 1 < 0, and the inequality cx2-bx + a > 0 is reduced to (α x + 1) (β x + 1) < 0, ∫ 0 < α < β, and the inequality cx2-bx + a > 0 is reduced to cax2 − Bax + 1 < 0, and the inequality CX2 + (α + β) x + 1 < 0 is reduced to (α x + 1) (β x + 1) < 0, ∫ 0 < α < β, ∫ 1 α < 1 β The solution set of equation cx2-bx + a > 0 is {x | 1 α < x < 1 β}



Tell, else, you, what, can, me


What else can you tell me



There is a round flower bed with a diameter of 8 m, and a 3 m wide path is built around it. What is the area of this path?


The area of the round flower bed = π (8 / 2) &# 178; = 16 π
Peripheral area = π (8 / 2 + 3) &# 178; = 49 π
The area of the path is 49 π - 16 π = 33 π



Dictionary (plural) scar (plural) kitchen (antonym) choose (past tense) person (adjective) expensive (comparative)
How to write "interesting" or "boring"?


dictionary---dictionaries
scarf---scarfs
cheap---expensive
choose---chose
person---personal
expensive---more expensive
interesting---interest
boring---interesting



In △ ABC, if (SINB + sinc): (sinc + Sina): (Sina + SINB) = 4:5:6, find the angle of the largest angle
A.60° B.90° C.120° D.150°


According to the sine theorem
(b/2R+c/2R):(a/2R+c/2R):(a/2R+b/2R)=4:5:6
A: B: C = 7:5:3,
Maximum angle a, cosa = (5 ^ 2 + 3 ^ 2-7 ^ 2) / (2 × 5 × 3) = - 1 / 2



Use the past tense, the future tense, the present tense, the present progressive tense and the present perfect tense to make sentences
If there is a specific sentence:
I watch TV.
She gets a new car.


I watched TV last weekend
I watch TV on the weekend
I am watching TV
I'm watching tvwith my mother
I have a watched TV
She got a new toast weekend
She get a new car on the weekend
She get a new car
She is getting a new car
She has got a new car



Junior high school chemistry (solubility calculation)
The key is the process
When the temperature is 20 ℃, the solubility of a solute is 88g / 100g water. When the temperature is 20 ℃, 15g of the solute is dissolved in 30g water___ Solution (saturated / unsaturated)
When the temperature is 10 ℃, there is 100g saturated solution of potassium nitrate. After the solution is heated and evaporated to dryness, the nitric acid crystal is 17.3g, and the solubility of potassium nitrate at 10 ℃ is 0.5%____ .
The key is the process


The solubility and mass fraction of the saturated solution remain unchanged at the same temperature
At 20 ℃, the solubility of a solute is 88g / 100g water
Then the mass fraction is: 88 / (88 + 100) = 46.8%
The mass fraction of 15g solute dissolved in 30g is 15 / (15 + 30) = 33.3%



What is the instantaneous capacitance voltage of a resistor, capacitor and inductor series circuit when it is switched on and off? Why?
The power supply in the circuit is DC power supply. I also want to ask, when the switch is not closed, what is the voltage at both ends of the capacitor and why?


At the moment of closing, the capacitor voltage is 0, because it takes time for the capacitor to charge. The length of time depends on the charging current, that is, the power supply voltage and resistance. In short, if there is time, the capacitor voltage will gradually increase during the charging process until it reaches the power supply voltage. At this time, there is no current in the circuit. When the switch is not closed, there is no voltage, because it is not powered on, the capacitor is not charged