How to solve the cross multiplication of x ^ 2 + 2ax-1 + 2A > 0?

How to solve the cross multiplication of x ^ 2 + 2ax-1 + 2A > 0?

Take the back one apart
Split into - 1 and (1 + 2a)
The final solutions are 1 and - (1 + 2a)

Cross phase multiplication factorization (as long as the answer) x * x-2x-1 x * x-2ax-3a * a * a * a * A-B * b * B x * x + X - (y * y + y)
x*x-2x-1
x*x-2ax-3a*a
a*a*a-b*b*b
x*x+x-(y*y+y)

X * x-2x-1 = (x-1 + radical 2) (x-1-radical 2)
x*x-2ax-3a*a =(x+a)(x-3a)
a*a*a-b*b*b=(a-b)(a^2+ab+b^2)
x*x+x-(y*y+y)=(x-y)(x+y+1)

Cross phase multiplication factorization factor X ^ 2-4ax + 3A ^ 2 + 2a-1

x^2-4ax+3a^2+2a-1
=(x-3a) (x-a) + 2a-1 (in brackets, x ^ 2-4ax + 3A ^ 2 cross multiplication)
=(x－3a＋1)(x－a－1)
x－3a 1
×
x－a ﹣1

Factorization: A ^ 2Y ^ 2-ay - (b-2) (B-3)

==(ay-b+2)(ay+b-3)

Given the linear function y = KX + B (B ≠ 0), the image is a straight line parallel to the straight line y = 4x
(1) With the increase of independent variable x, does function value y increase or decrease
(2) Which quadrants does the line y = KX + 2 pass through
(3) The line y = KX + B (B is not equal to 0) passes through those quadrants

3123 or 134

The prime factor of 42 is, the prime factor of 60 is, 42 and
The prime factors of 42, 60, 42 and 60 are the same

2#3#7
2#3#5
2#3

We know that a + B = 6, ab = 8, and a > B
1.a³b+ab³
2.3a²-6ab+3b²
3.a²-b²-10b-25

1.224
two point one two
3.-33

The value of the Nth derivative of F (x) = x ^ 2 / (1-x) at x = 0

The method of this problem is to write f (x) as the sum of two simple fractions. I suggest you master the method of decomposition, because indefinite integral
We need it when we need it
Let x ^ 2 / (1-x) = (x ^ 2-1 + 1) / (1-x) = - X-1 + 1 / (1-x),
f(x)＝1/(1-x)-x-1
After a few simple steps of derivative operation, we know that the n-order derivative is
f^n(x)＝n!/(1－x)^(n+1)
f^n(0)＝n!/(1－0)^(n+1)=n!
The value of the n-th derivative of F (x) = x ^ 2 / (1-x) at x = 0 is n!

Simple calculation 12.1 - (1 / 35 + 1 / 21) X105

The original formula is 12.1-1 / 35 × 105-1 / 21 × 105
＝12.1－3－5
＝4.1

Two fifths is its reciprocal

16