If two images with inverse scale function y = m / X are distributed in the second and fourth quadrants, then which quadrant is the point (m, m-2)?

If two images with inverse scale function y = m / X are distributed in the second and fourth quadrants, then which quadrant is the point (m, m-2)?

According to the meaning of the question, if the inverse proportion function is divided into the second and fourth quadrants, there is m

It is known that y = (M2 − 5) XM2 − m − 7 is the inverse proportion function of Y with respect to x, and the image is in the second and fourth quadrants

From the meaning of the question, we can get: M2 − m − 7 = − 1 − M2 − 5 < 0; solve the equation: M1 = - 2, M2 = 3. But M2 = 3 is not the meaning of the question, so m = - 2

As shown in the figure, it is a branch of the image with inverse scale function y = (M + 3) / X (the curve is in quadrant 2 / 4)
The range of constant M
If the image passes through the point (- 1,3), the,
When m = - 6, take any point a (a, b) on the function. If B < 3, what is the value range of a?

y=-3/x
y=-3/x,ab=-3,b

The average number of the three numbers is 120. A is twice that of B. C is 5 more than A. what are the three numbers of a, B and C?

It's OK to set up equations
Let a be X
Then: x + X / 2 + X + 5 = 120 * 3
X=142
y=71
z=147

The equation cos2x + 2sinx + 2m-3 = 0 has exactly two different real number roots in the interval [0,2]. The value range of M and the root of the equation are obtained

Khan, I have done a lot of such questions today
Solution: cos2x = 1 - (SiNx) ^ 2 is substituted into the condition
1-(sinx)^2＋2sinx＋2m－3＝0
Simplification
(sinx-1)^2=2m-1
-1

1×1×9×9×9×9×8×7×6×5×4×3×2×120

31744742400

Let a and B be two different solutions of a system of non-homogeneous linear equations AX = B
Let a and B be two different solutions of a system of non-homogeneous linear equations AX = B
A. A + B is the solution of AX = B. A-B is the solution of AX = B
C. 3a-2b is the solution D of AX = B, 2a-3b is the solution D of AX = B

There is a knowledge point to remember:
The linear combination of solutions of non-homogeneous linear equations is still its solution if and only if the sum of combination coefficients is equal to 1
A. The sum of the combination coefficients is 1 + 1 = 2, which is not true
B. 1-1 = 0 is wrong
C. 3-2 = 1 correct
D. 2-3 = - 1 is wrong
Correspondingly, the linear combination of the solutions of the system of non-homogeneous linear equations is the solution of the derived system if and only if the sum of the combination coefficients is equal to 0

It is known that the ratio of work efficiency of Party A and Party B is 5:4. How many days does it take for Party A to complete this batch of parts alone?

120 × 59 = 1361 △ 136 = 36 (days) a: it takes 36 days for Party A to make this batch of parts alone

Solve the equation 65 - (2x + 1) (4x ^ 2-2x + 1) + 8x (x + 2) ^ 2 = 32 (x-3) ^ 2

65-（2x+1)(4x^2-2x+1)+8x(x+2)^2=32(x-3)^265+8x(x^2+4x+4)=32(x^2-6x+9)+（2x+1)(4x^2-2x+1)65+8x^3+32x^2+32x=32x^2-192x+288+8x^3-4x^2+2x+4x^2-2x+1224x=224x=1

The quality ratio of chemical fertilizer in warehouse A and warehouse B was 12:11. Later, 24 tons of chemical fertilizer were transported to warehouse B. at this time, the chemical fertilizer in warehouse A was less than that in warehouse B. 19. How many tons of chemical fertilizer were stored in warehouse B?

24 △ 1 (1-19) - 1112] × 1112 = 24 △ 89-1112] × 1112, = 24 △ 98-1112] × 1112, = 24 △ 524 × 1112, = 105.6 tons. A: the original warehouse B is 105.6 tons