A substance weighs 49n and has a volume of 5x10 to the negative fifth power M & sup3;. When it is put into water, the buoyancy it receives is

A substance weighs 49n and has a volume of 5x10 to the negative fifth power M & sup3;. When it is put into water, the buoyancy it receives is


First calculate the density of the object ρ = m / v = (49 / 9.8) / [5 * 10 ^ (- 5)] = 1 * 10 ^ 5kg / m3
Obviously, the density of an object is greater than that of water, so the object will sink to the bottom and come to rest
The buoyancy is f = ρ water * g * V = 1 * 10 ^ 3 * 9.8 * [5 * 10 ^ (- 5)] = 0.49 n



The buoyancy of an object suspended in kerosene is 15.68n. (1) calculate the volume of the object; (2) if the object is put into water, what is the volume of the object above the water? (g = 10N / kg, kerosene density is 0.8 × 103kg / m3)


(1) When the object is suspended in kerosene, its volume v = V, kerosene discharge = F & nbsp; kerosene floatation g = 15.68n0.8 × 103kg / m3 × 10N / kg = 1.96 × 10 ~ (- 3m3); (2) when the object is suspended in kerosene, its volume v = V, kerosene discharge = F & nbsp; kerosene floatation g = 15.68n0.8 × 103kg / m3, kerosene floatation g = 15.68n, kerosene floatation



As shown in the figure, the quadrilateral ABCD and debf are rectangular, ab = BF, ad and be intersect at m, BC and DF intersect at n


It is proved that: ∵ quadrilateral ABCD and debf are rectangles, ab = BF, ≌ ABM = ≌ FBN, ≌ ABM ≌ FBN ≌ EDM, ≌ BN = DM, ≌ quadrilateral bmdn is parallelogram, similarly, ≌ ABM ≌ FBN, then BM = BN, ≌ quadrilateral bmdn is diamond



Y = e ^ t * cost, x = e ^ t * Sint, find y '. How can I use y' = (y '` to get a different result from y' = D (dy / DX) / DX?


Sorry to hit! There is a mistake in these two methods! (y ')' is wrong. For parameter equation, use the second method



In a big square of 4 * 4 (composed of a small square with 16 sides)
How many triangles have three vertices on the vertex of a small square
Ah, help! 3Q!


Types of right triangle: (divided by right side)
1,1
1,2
1,3
1,4
2,2
2,3
2,4
3,3
3,4
4,4
10 species in total



There are 6 columns, each of which is 1.57m in circumference and 6m in height. If the column is repainted, the area to be painted should be calculated


What is painted is the side area of the cylinder
1.57 × 6 × 6 = 56.52 (M2)



Add appropriate operation symbols or brackets in the middle of the number to make the formula hold that 5 is equal to 2 5 5 is equal to 4


5 divided by 5 + 5 divided by 5 = 2
(5 X5 - 5) divided by 5 = 4



Is the first partial derivative continuous when the function of two variables is differentiable?
If not, please give an example?


It's not right
Partial derivative continuous differentiable continuous limit
Differentiability with partial derivation
For this question
Such as function
Z = (x2 + Y2) sin (x2 + Y2) (- 1 / 2) when x2 + Y2 is not equal to zero
0 when x2 + Y2 equals zero



Xiao Ming has a cuboid glass fish tank, 5.2 decimeters long, 3.2 decimeters wide and 3.6 decimeters high. The glass is 1 cm thick. What is the volume of this glass cubic decimeter


1 cm = 0.1 decimeter
Volume = (5.2-0.1-0.1) × (3.2-0.1-0.1) × (3.6-0.1) = 52.5 cubic decimeter



Can you calculate 2001 or 2002 by adding, subtracting, multiplying, dividing and parenthesis?
8 can not be connected together, such as 88888, etc
If you can, please give the algorithm. If you can't, please give a detailed proof.


It should not be,
In 2001, the final requirement is + 1, that is, 8 / 8, and at least 8 * 8 * 8 * 4, that is, 8 * 8 * 8 * 8 / (8 + 8). The remaining 8 can't be put anywhere;
2002, same as above, at least add 2, that is (8 + 8) / 8