It takes Xiao Li 6 hours and Xiao Wang 5 hours to print a manuscript. Two hours later, there are still 600 words left. How many words are there in this manuscript?

It takes Xiao Li 6 hours and Xiao Wang 5 hours to print a manuscript. Two hours later, there are still 600 words left. How many words are there in this manuscript?

1 - (2 / 6 + 2 / 5) = 4 / 15600 * 15 / 4 = 2250 words

Xiao Wang printed a manuscript. If he typed 95 words per minute, it would be 20 minutes later than the plan. If he typed 107 words per minute, it would be 10 minutes faster. The original plan was to finish the manuscript in a few minutes

Xiao Wang printed a manuscript. If he typed 95 words per minute, it would be 20 minutes later than the plan. If he typed 107 words per minute, it would be 10 minutes faster. The original plan was (247.5) minutes
Set the original plan to finish the task in X minutes
95（x+20）=107(x-10)
95x+1900=107x-1070
107x-95x=1900+1070
12x=2970
x=247.5
If you don't understand, please ask

Aunt Wang typed a 15000 word manuscript, and she finished three fifths of the book three days ago. According to this calculation, how many days will it take for Aunt Wang to finish the manuscript?

15000 × 3 / 5 = 9000
9000÷3＝3000
15000÷3000＝5
5－3＝2

There is a mathematical problem, from 123456789 to insert a minus sign, three plus signs, the final result is 72?
Must meet the requirements

12 +3 +45 - 67 + 89 = 82
12+34+5-67+89 = 73
.
Is this problem unsolved?

The relationship between quadratic function and quadratic equation of one variable
How to find the intersection coordinates of parabola y = - x ^ 2 + 4x + 5 and X axis Y axis?
How many intersections does the parabola y = x ^ 2-6x + 9 have with the X axis?

（1）
Let y = - x ^ 2 + 4x + 5 = 0
x²-4x-5=0
(x-5)(x+1)=0
X = 5 or x = - 1
So the intersection coordinates of y = - x ^ 2 + 4x + 5 and X axis are (5,0), (- 1,0)
Let x = 0 be y = 5
So the intersection coordinate of y = - x ^ 2 + 4x + 5 and Y axis is (0,5)
（2）
Y = x ^ 2-6x + 9 = 0
(x-3)²=0
x=3
So there is an intersection with the x-axis, which is (3,0)

Use 3 4's and 1's to form a mathematical formula, so that the sum is 15. You can use the plus sign, minus sign, multiplication sign, division sign, bracket, which can be used repeatedly

(4-1/4)*4=15

1: The equation (x + 2) (X-2) = 4x-1 is reduced to the general form (), where b-squared-4ac = ()
2: The equation 2x square - 3 = 4x, where b square - 4ac = (), the root of the equation is (). 3: the root formula of quadratic equation with one variable is derived by () method

1: The equation (x + 2) (X-2) = 4x-1 is reduced to the general form (X & # 178; - 4x-3 = 0), where b-squared-4ac = (28). 2: the equation 2x-squared-3 = 4x, where b-squared-4ac = (40), the case of the roots of the equation is (2 / 2 (2 + radical 10), and 2 / 2 (2-radical 10)). 3: the solution of quadratic equation of one variable

In the linear regression equation of one variable, the sign of regression coefficient and correlation coefficient is consistent, and the sign can be used to judge the phenomenon
1. Linear correlation or nonlinear correlation
2. Positive correlation or negative correlation
3. Single correlation or multiple correlation
4. Complete correlation or incomplete correlation

2. Positive correlation or negative correlation

High school mathematics definite integral related problems, online, etc
How to find the area of trapezoid with curved edge enclosed by straight line x = 0, x = 2, y = 0 and curve y = x ^ 2?
Today, I just learned definite integral. I don't understand it. It's mainly about the part of summation. Please give me an answer
Sorry, everyone. The example in our textbook is to calculate the area according to "replacing the curve with the straight line". Your formulas are useless to me

The area of trapezoid with curved edge enclosed by straight line x = 0, x = 2, y = 0 and curve y = x ^ 2
Integral sign (upper 2, lower 0) (x ^ 2-0) DX = x ^ 3 / 3 | (upper 2, lower 0) = 2 ^ 3 / 3-0 = 8 / 3
Using "straight instead of curved" to calculate area
Then you can evenly take a few points between 0 and 1, such as 5 or 10 points, and then calculate the area of each small trapezoid separately, and then add them all up

The first volume of the sixth grade mathematics problem is published by Jiangsu Education Press: the 3.4.5 of the 16 sides of the mathematics exercise book and the thinking problem and the 678 of the 29 sides of the mathematics book and the thinking problem

3. Set the depth of water in the tank × decimeter
24 times 5 × = 360
24 times 5 × / 24 = 360 ／ 24
5×=15
×=3
A: the water depth in the tank is 3 decimeters
5.1.2×0.8×（0.7-0.2）
=1.2×0.8×0.5
=0.96×0.5
=0.48（m3)