It is known that the effective value of sinusoidal current I = 1, f = 50 Hz, and the initial position π / 3. The instantaneous value expression and waveform are obtained

It is known that the effective value of sinusoidal current I = 1, f = 50 Hz, and the initial position π / 3. The instantaneous value expression and waveform are obtained


i=Isin(2πft+ψi)=√2sin(100πt+π/3).ψi=π/3=60°. 
 



In nonsinusoidal periodic current circuit, the relationship between the effective value of each harmonic and the amplitude is simple
Ak=____ Akm.


The relationship between RMS and amplitude of each harmonic is 1:1.414 [root 2],
The relationship between amplitude and amplitude is 1.414 times
It's very simple: harmonics of any order are sine waves. That's all



How to calculate angular frequency in sinusoidal current circuit


The angular frequency is equal to 2 π times of the frequency, that is, ω = 2 π F



Let F: X → - x2 + 2x be the mapping from real number set M to real number set n. if there is no primitive image in M & nbsp; for real number P ∈ n, then the value range of P is______ (set or interval representation)


∵ y = - x2 + 2x = - (x-1) 2 + 1 ≤ 1 ∵ the range of function is (- ∞, 1] ∵ for real number P ∈ n, there is no prime image in set M, ∵ P > 1. So the answer is: (1, + ∞)



How to do the simple calculation of 26 * 19 + 13 * 19 + 39 * 81


26*19+13*19+39*81
=(26+13)*19+39*81
=39*19+39*81
=39*(19+81)
=39*100
=3900



Given the line L: x-2y-2 = 0, find: 1. The equation of the symmetric line of the line L with respect to (2,3); 2. The equation of the symmetric point of the point (2,3) with respect to the line L


For (2,3) symmetry, if the equation coordinates of L are (x, y), then the symmetric point (x1, Y1) of l about (2,3) satisfies: l: x1-2y1-2 = 0. Then: (x1 + x) / 2 = 2 (Y1 + y) / 2 = 3x1 = 4-xy1 = 6-y, and substitute x1-2y1-2 = 0 (4-x) - 2 (6-y) - 2 = 04-x-12 + 2y-2 = 0-x + 2y-10 = 0 into x1-2y1-2 = 0



What are the 21st-30th in English words?


twenty first ,twenty second ,twenty third ^………… thirtyth



How to expand a function into a power series?
The final exam is coming soon. This is the last question of filling in the blanks. I don't want to read a long book, as long as I can deal with this question. Let's talk about it briefly


First determine which point to expand, first write the function in the form of a / (cx-d), use (x-x *) to transform the original formula into the form of 1 / (1-f (x-x *), then you can expand it. Note that the convergence domain is f



What multiplied by 1 is equal to 52
The title is as follows:
( )*1( )( )( )=( )( )5 2


(4)*1(7)(3)(8)=(6)(9)5 2
4*1378=6952
1-9 each number appears once



The function f (x) = a to the x power holds f (x) on (- 2,2)


When a = 1, f (x) = 1