The radius ratio of circle a and circle B is 3:5, the perimeter of circle a is 30 meters, and the area of circle B is 50 square meters

The radius ratio of circle a and circle B is 3:5, the perimeter of circle a is 30 meters, and the area of circle B is 50 square meters

Classmate. It's impossible

Taking sides AB and AC of triangle ABC as sides, square ABDE and square acfg are made outwards respectively, connecting eg, trying to judge the relationship between triangle ABC and triangle AEG area, and giving reasons

If the area of △ ABC and △ AEG is equal, passing point C is cm ⊥ AB in M, passing point G is GN ⊥ EA, intersecting EA extension line in N, then ⊥ AMC = ⊥ ang = 90 °, ⊥ Quad ABDE and Quad acfg are square, so ⊥ BAE = ⊥ CAG = 90 °, AC = AG, ⊥ EAB ⊥ GAC = 180 °⊥ BAC ⊥ EAG = 180 °⊥ EAG ⊥ Gan

Arc length 8.34m chord length 6.3m radius

Arc length C = 8.34m chord length L = 6.3m radius r?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=3
R1=3.249
R2=3.305
R3=3.308
R4=3.308
R = 3.308m

Xiao Liang is doing continuous natural numbers 1, 2, 3, 4, 5 When summing, add one more time, and the result is 149. Then the number added is () a.13 B.14 c.15 d.16

Let the multiple addend be X
（N+1)N/2=149-X
(n + 1) n = 298-2x the multiplication of adjacent natural numbers is less than 298
16*17=298-2X
272=298-2X
X=13
Choose a

The verse of the wanderer's song

The thread in the mother's hand is the coat of the wanderer's body
I'm afraid I'll be late when I leave
Who said inch grass heart, reported three spring

On the image and properties of inverse scale function
We know that the intersection of y = KX + B and m of y = x is a (- 2,1) and B (1, n)
Find: (1) the expression of two functions, (2) the area of triangle AOB

1, bring in B, get n = 1
Bring in a, get two binary quadratic City, get k = B=
2a0b area, bottom, 3, height is 1, area =

A cuboid has a surface area of 78 square centimeters, a bottom area of 15 square centimeters and a bottom perimeter of 16 centimeters

The perimeter of the bottom surface is 16 cm
16 △ 2 = 8 cm (L + W)
78 △ 2-15 = 24 square centimeters (L × H + W × h)
24 △ 8 = 3 (high)
Volume = 15 × 3 = 45 CC

Sin, cos, Tan problems
【1+cos（π + X )】【1- cos（π - X）】=

【1+cos（π + X )】【1- cos（π - X）】
=【1+cos（π + X )】【1- cos（X-π）】
=【1+cos（π + X )】【1- cos（2π+X-π)】
=【1+cos（π + X )】【1- cos（π+X）】
=1-cos²(π+X)
=sin²(π+X)
=sin²X

If LGA and LGB are the two roots of equation x2-4x + 1 = 0, find the value of [LG (A / b)] ^ 2

Because
LGA and LGB are the two roots of the equation x2-4x + 1 = 0,
therefore
lga+lgb=4,lga*lgb=1
thus
[lg(a/b)]^2=(lga-lgb)^2
=(lga+lgb)^2-4lga*lgb
=4^2-4*1
=16-4
=12

Why is the value range of the independent variable in the root X of function y = x + 1 greater than or equal to 0 instead of greater than 0

Because when it is equal to 0, y = 0 satisfies the function definition