A = [1 1 - 1 2 10 1 - 1 0] find the inverse matrix of a by elementary row transformation,

A = [1 1 - 1 2 10 1 - 1 0] find the inverse matrix of a by elementary row transformation,

A = [11 - 121 01 - 10] elementary transformation (a, e) = [11 - 110 02 100 01 - 1000 01] 1. Change the first column elements of the second and third rows to 0, specifically (- 2) times of the first row elements added to the second row; (- 1) times of the first row elements added to the second row; (a, e) [1

By using the elementary transformation of matrix, the inverse matrix 3-20-10221-2-3-20121 of square matrix is obtained

3 -2 0 -1 1 0 0 00 2 2 1 0 1 0 0 1 -2 -3 -2 0 0 1 00 1 2 1 0 0 0 1r1-3r30 4 9 5 1 0 -3 00 2 2 1 0 1 0 0 1 -2 -3 -2 0 0 1 00 1 2 1 0 0 0 1r1-2r2, r3+r2,r2...

Given the square of a + the square of B = 8A + 4b-20, find the power of (1 / 2)
Given that the square of a + the square of B = 8A + 4b-20, find the power of 2008 of (1 / 2) multiplied by (a-b) + (- 8A to the third power, B to the second power) / (2Ab) to the second power
That kind-hearted person is in a hurry to help~~~~~~~~~~~~~~

The equation A & # 178; + B & # 178; = 8A + 4b-20 can be reduced to: A & # 178; - 8A + 16 + B & # 178; - 4B + 4 = 0 (A-4) & # 178; + (b-2) & # 178; = 0. To make the above equation true, we must make: A-4 = 0 and B-2 = 0 solve a = 4 and B = 2, so the power of (1 / 2) of 2008 times the power of (a-b) + (- 8A & # 179; B & # 178;) / (2Ab

How to remove t from the parametric equation and change it into the ordinary equation x = R (3cost + cos3t) y = R (3sint-sin3t)

Because sin3t = 3sint-4 (Sint) ^ 3, cos3t = 4 (cost) ^ 3-3cost
So: 3sint-sin3t = 4 (Sint) ^ 3; 3cost + cos3t = 4 (cost) ^ 3
Then, x = 4R (cost) ^ 3; y = 4R (Sint) ^ 3
===> (cost)^3=x/4r；(sint)^3=y/4r
===> (cost)^2=(x/4r)^(2/3)；(sint)^2=(y/4r)^(2/3)
===> (x/4r)^(2/3)+(y/4r)^(2/3)=1

Mathematical factorization cross method
How to use that method of drawing cross? Now I forget that name. I just wrote one yuan quadratic scale to use. Now I won't

Cross multiplication, I'll give you a few examples
The main method is diagonal multiplication
For example, x ^ 2 + 3x + 2 = 0
Split the coefficients before x ^ 2 and 2 (that is, 1 and 2)
1 * 1 = 1 * 2 = 2 so
1 2
1 1
The result of diagonal multiplication is 1 * 2 + 1 * 1 = 3
The number obtained is equal to the coefficient in front of X, so it holds
It can be reduced to (x + 2) (x + 1) = 0
If not, there is a detailed explanation here, which is troublesome
Methods first, the quadratic term is decomposed into (1 x quadratic coefficient), Decompose the constant term into (1 x constant term) and write the third a = 2 b = 1 C = quadratic term coefficient △ a d = constant term △ B the fourth a = 2 b = 2 C = quadratic term coefficient △ a d = constant term △ B the fifth a = 2 b = 3 C = quadratic term coefficient △ a d = constant term △ B the sixth a = 3 B = 2 C = quadratic term coefficient △ a d = constant term △ B the seventh a = 3 B = 3 C = quadratic term coefficient △ a D = constant term △ B. and so on until (AD + CB = coefficient of first term). The final result format is (AX + b) (Cx + D)
I hope it can help you
You can keep asking me if you don't know

If the image of the line y = 3x + m and the line y = - 5x-1 / 3N intersects at a point on the X axis, then M: n=

When y = 0, M = - 3x; n = - 15x; then M: n = 1:5

Find limit limx → 1, x ^ 4-1 / x ^ 3-1

Lobida's law 4x ^ 3 / 3x ^ 2 = 4x / 3 = 4 / 3

Fill in the blanks of quadratic function (2.4, 2.5 test questions) in Junior Three
1. The parabola y = - 2x & sup2; + 4x + 3 is transformed into y = a (X-H) & sup2; + K__________ .
2. Given the parabola y = - 2 (x + 3) & sup2; + 5, if y decreases with the increase of X, then the value range of X is_______ .
3. Please write the expression of a quadratic function that meets the following three conditions:______________ .
① Passing point (3,1)
② When x > 0, y decreases with the increase of X
③ When the value of the independent variable is 2, the value of the function is less than 2

1. The parabola y = - 2x & sup2; + 4x + 3 is transformed into y = a (X-H) & sup2; + K___ y=-2(x-1)^2+5_______ 2. Given the parabola y = - 2 (x + 3) & sup2; + 5, if y decreases with the increase of X, then the value range of X is x > - 3_______ 3. Please write a quadratic function that meets the following three conditions

Solve a system of linear equations with two variables
Solving {2x + 3Y = 0
3x-y=11

Multiply the second equation by 3 to get 9x-3y = 33. Add the first equation to get 11x = 33, x = 3, y = - 2

The intersection of the U-I diagram of the resistance and the U-I diagram of the power supply is the U-I diagram of the resistance at this time
The intersection of the U-I diagram of the resistance and the U-I diagram of the power supply is the U and I of the resistance at this time. Why
The intersection of the U-I diagram of the resistance and the U-I diagram of the power supply is the U and I of the resistance at this time. Why?

The current passing through the power supply and the current passing through the external resistance must be the same, so the current at the intersection is the current of the resistance. At this time, the U corresponding to the resistance is naturally the U of the resistance. The U of the power supply is the output voltage, that is, the total voltage of the external circuit. If the external circuit has only one pure resistance in series, the above phenomenon will appear