The original number of female workers in a workshop accounted for 14% of the total number of workers in the workshop, and then the number of male and female workers increased by 4 respectively. At this time, the number of female workers accounted for 13% of the total number of workers in the workshop. How many were the original workers in the workshop?

The original number of female workers in a workshop accounted for 14% of the total number of workers in the workshop, and then the number of male and female workers increased by 4 respectively. At this time, the number of female workers accounted for 13% of the total number of workers in the workshop. How many were the original workers in the workshop?

Decomposition factor: 9 (M + n) & sup2; + 6m + 6N + 1

9(m+n)²+6m+6n+1
=9(m+n)²+6﹙m+n﹚+1
=﹙3m＋3n＋1﹚²

The ratio of male and female students in the school chorus was 5:4, and then two female students were added. This is the ratio of male and female students, which was 10:9. Originally, there were male and female students in the chorus
emergency

There are x boys and y girls
From the question: X / y = 5 / 4
x/y+2=10/9
=>4x=5y
9x=10y+20
The solution is x = 20, y = 16

After simplification, we can evaluate: X-2 (3y2-2x) - 4 (2x-y2), where | X-2 | + (y + 1) 2 = 0

∵||x-2 | + (y + 1) 2 = 0, ∵ x = 2, y = - 1, X-2 (3y2-2x) - 4 (2x-y2) = x-6y2 + 4x-8x + 4y2 = - 3x-2y2, when x = 2, y = - 1, the original formula = - 6-2 = - 8

There are 54 students in class 62, 80% of whom are girls. How many girls are there in class 62

There are x boys and 0.8x girls
So x + 0.8x = 54
1.8x=54
x=30
So female = 30 * 0.8 = 24
Please accept

Ax ^ 2-6x-12 = (3x-3) (KX + 4) find the value of a + k

ax^2-6x-12=3kx^2-3kx+12x-12
So a = 3k, - 6 = - 3K + 12
k=8,a=24
a+k=32

Number a is 20% more than number B, and number B is 25% less than number a (right or wrong)

Wrong
Less = 20% / (1 + 20%) = 1 / 6

The opposite number of a is - A, and a can be not only positive, but also negative or 0

Absolutely no problem. That's right

Team a, team B and team C completed a road together. Team a said that half of the total task had been completed. Team B built 120 meters. Team C took 30% of the total length
How long is the road? It's fast

The total length is x meters;
Formula: 0.5x + 120 + 0.3x = x
X = 600m
Or:
Team a said that it has completed half of all tasks, that is, team a has completed 50% of all tasks
Team C took up 30% of the total length,
So B completed 1-30% - 50% = 20%
Because team B repaired 120 meters
So 120 / 20% = 600 meters

If the equation x ^ 2sin2 θ + y ^ 2cos θ = 1 represents an ellipse, then the value range of θ is

sin2θ＞0
2sinθcosθ＞0
cosθ＞0
therefore
sinθ＞0,cosθ＞0
Namely
2kπ＜θ＜2kπ＋π/2
but
sin2θ≠cosθ
2sinθ≠1
sinθ≠1/2
θ≠2kπ＋π/6
therefore
What is the range of theta
2kπ＜θ＜2kπ＋π/2
but
θ≠2kπ＋π/6