The equation for finding the line parallel to the line 3x + 4y-12 = 0 and the distance from it is

The equation for finding the line parallel to the line 3x + 4y-12 = 0 and the distance from it is

What's the distance
You can set up a linear equation
3x+4y+c=0
Then, it is calculated according to the distance formula

If f (x) is a monotone decreasing function in the interval [- 3,0], we know that the even function f (x) defined on R satisfies f (3 + x = f (3-x)
Then a = f (1.5), B = f (√ 2), C = f (4)

Even function f (x) defined on R, the image is symmetric about y axis
∵ satisfy f (3 + x = f (3-x)
The f (x) image is symmetric with respect to x = 3
∵ f (x) is a monotone decreasing function in the interval [- 3,0]
According to Y-axis symmetry
On [0,3], f (x) is an increasing function
According to f (x), the image is symmetric with respect to x = 3
∴f(4)=f(2)
∵√2

The coordinates of the intersection of the line y = 2x-1 and the parabola y = x2 are ()
A. （0，0），（1，1）B. （1，1）C. （0，1），（1，0）D. （0，-1），（-1，0）

The analytic formula of simultaneous two functions can be obtained as follows: y = 2x − 1y = X2, and the solution is: x = 1y = 1. That is to say, the coordinates of the intersection of the straight line y = 2x-1 and the parabola y = x2 are (1,1). Therefore, B

It is known that the symmetry axis of the parabola y = ax + BX-1 is a straight line x = - 1, and its highest point is on the straight line y = 2x + 4. The intersection and coordinates of the parabola and the straight line are obtained

Because the axis of symmetry is x = - 1, so - B / (2a) = - 1. (1) because the highest point is on the straight line y = 2x + 4, so the highest point is the intersection of x = - 1 and y = 2x + 4, which is (- 1,2), so a-b-1 = 2. (2) simultaneous (1) (2) formula solution gives a = - 3, B = - 6, so simultaneous y = - 3x ^ 2-6x-1, and the x = - 5 / 3 or x = - 1 of y = 2x + 4 solution gives corresponding y = 2 / 3 or y = 2, so the intersection coordinates are (- 5 / 3,2 / 3) and (- 1,2)

The sum of two prime numbers 39, what is the product of these two prime numbers?

In prime numbers, 2 is the only even number, and the rest are odd numbers
If you want the sum to be 39, you must have an even number plus an odd number
So 39 = 2 + 37
2*37=74

Given that real numbers a and B satisfy √ A / b (√ AB + 2b) = 2 √ AB + 3b, then a / b

The multiplication on the left is reduced to (AB under a + 2 radical)
So the equation is reduced to a = 3B
So a / b = 3

4(x-2)²-(x-1)²=0
3x & # 178; - 2-2x radical 3 = 0 X & # 178; + 5 = 2x radical 5x & # 178; + ax-2a & # 178; = 0

4(x-2)²-(x-1)²=0
[2(x-2)-(x-1)][2(x-2)+(x-1)]=0
（2x-4-x+1）（2x-4+x-1）=0
(x-3)(3x-5)=0
X = 3 or x = 5 / 3
3x & # 178; - 2-2 times root 3 = 0
3x square = 2 + 2 √ 3
Is the title wrong
X & # 178; + 5 = 2x radical 5x
X square - 2 √ 5x + (√ 5) square = 0
(x - √ 5) square = 0
x1,2=√5
x²+ax-2a²=0
(x-a)(x+2a)=0
X = a or x = - 2A

First simplify and then evaluate; 7a & # 178; B + (- 4AB & # 178;) - (7a & # 178; b-3ab & # 178;) - 5ab, where a = 2, B = 1

The original formula = 7a & # 178; b-4ab & # 178; - 7a & # 178; B + 3AB & # 178; - 5ab
=-ab²-5ab
=-2-10
=-12

Is x + 1 / 2x = 2 a linear equation with one variable

No

The determinant / A / of n-order matrix A is 0, and its adjoint matrix A * determinant is 0. Why?
RT

If | a | = 0, assuming | a * | is not equal to 0, then a * is reversible, that is, (a *) ^ - 1 times a * = E
Then a = AA * (a *) ^ - 1 = | a | (a *) ^ - 1 = 0
That is, a is a 0 matrix, and its adjoint matrix is also a 0 matrix, which contradicts that | a * | is not equal to 0
Get proof