Given the sequence an, A1 = 1, an + 1-an = 2

a1=1
a2-a1=2
a3-a2=2∧2
.
a(n-1)-a(n-2)=2∧n-2
an-a(n-1)=2∧n-1
Add the left and right sides of each equation to get: an = 1 + 2 + 2 Λ 2 +. + 2 Λ n-2 + 2 Λ n-1 = 2 Λ n-1

In the sequence {an}, A1 = 1, the nth power of a (n + 1) = (1 + 1 / N) an + (n + 1) / 2, let {BN} = an / N, find the formula of the sequence {BN}

A (n + 1) = (1 + 1 / N) an + (n + 1) / 2 ^ n, that is, a (n + 1) = [(n + 1) / N] an + (n + 1) / 2 ^ n is obtained by dividing both sides of a (n + 1) / (n + 1) = an / N + 1 / 2 ^ n by N + 1, that is, B (n + 1) = BN + 1 / 2 ^ n shift term B (n + 1) - BN = 1 / 2 ^ n. ① because A1 = 1, BN = 1 / 1 = 1, by the formula b2-b1 = 1 / 2 ^ 1b3-b2 = 1 / 2 ^ 2b4-b3 = 1 / 2 ^ 3 bn-b(...

There are three piles of candy, of which the first pile has more pieces than the second pile, and the second pile has more pieces than the third pile. If one piece is taken out of each pile of candy, the number of the first pile of candy is three times that of the second pile. If the same number of pieces are taken out of each pile of candy, so that there are 32 pieces left in the first pile, the number of candy left in the second pile is two times that of the third pile How many pieces of candy are there at most?

Let X-1 = 3 (Y-1) ①, x-m = 32 ②, y-m = 2 (Z-M) ③. By simplifying the above three formulas, we can deduce x + y + Z = 49 + 2m, M = x-32 and M = 3y-34. The maximum value of M is 32 pieces, obviously 113 pieces. A: there are 113 pieces of candy in the three piles

If a * b = 3a-2b and 2 * 5 = - 4, then 2 * (- 5) =?

2*（-5）=3*2-2*（-5）=6-（-10）=16

It is known that the two roots of the quadratic equation AX ^ 2 + BX + C = 0 with respect to the real coefficient of X in the complex set are α, β. In the following conclusion, it is ()
A. α and β are conjugate complex numbers
B.α+β=-b/a,αβ=c/a
C.△=b^2-4ac>0
D.│α-β│=√(α+β)^2-4αβ

What holds is B. the relation between the root of quadratic equation and coefficient
A quadratic equation may have two unequal real roots
C discriminant may be negative (equation has no real root)
D is positive on the left and negative on the right

There are 200 kg apples in the fruit shop. The weight of pears is 4 / 5 of that of apples and 2 / 3 of that of peaches. How many kg are peaches?

Pear mass = 200 × (4 / 5) = 160 kg;
Peach weight = 160 △ 2 / 3 = 240 kg;
If you have any questions, please ask~~

In a triangle, angle 1 equals 65 degrees and angle 2 equals 40 degrees. So what triangle is it?

According to the conditions given in the title, the three angles of a triangle are 65 & # 186; 40 & # 186; 75 & # 186;, so they can only be acute angle triangles
This is my conclusion after meditation. If I can help you, I hope you will give me a chance to adopt it. If I can't, please ask, I will try my best to help you solve it

Finding sine value of space vector
For example (2 * 4 * 6) (1 * 9 * 7)

Let a = (2,4,6), B = (1,9,7), | ijk | a × B = | 246 | 197 | = - 26i-8j + 14K, a × B = (- 26, - 8,14), | a × B | = √ [26 ^ 2 + (- 8) ^ 2 + 14 ^ 2] = 2 √ 234, | a | = √ (2 ^ 2 + 4 ^

A primary school organized students to line up for an outing, and the walking speed was 1 meter per second
Arrived at the head of the line, then immediately returned to the end of the line, shared 10 seconds. How long is the line?
x/1.5＋x/3.5＝10
x＝10.5
How do I figure out 10.5? How do I figure out 2
Please give an example of the correct calculation process,

X / 1.5 + X / 3.5 = 10, 10.5 on both sides at the same time
7x+3x=105
10x=105
X=105/10
x=10.5

2 × 8N × 16N = 2 to the 22nd power
The power and product of the seventh grade junior high school students
Come on

Octave of 2 * 22nd power of n = 2
The 14th power of n = 2

Given the sequence an, A1 = 1, an + 1-an = 2