The definition field of function y = 1 / √ (3x-2) + LG (3x-1) is?

The definition field of function y = 1 / √ (3x-2) + LG (3x-1) is?

The root sign is 3x-2 ≥ 0
The denominator is not equal to 0
So 3x-2 > 0
x>2/3
True number 3x-1 > 0
x>1/3
So x > 2 / 3
Domain of definition (2 / 3, + ∞)

The domain of the function y = LG (3x-2)

From 3x-2 > 0
It is concluded that x > 2 / 3

The zero point of the function y = log2 (x-1) is

It's when y is zero
Then x = 2 to the power of Y + 1
y=0,x=2
The zero point is (2,0)

The numerator and denominator of a true fraction only contain prime factors 3 and 5. The greatest common factor of the numerator and denominator is 75
The numerator and denominator of a true fraction only contain prime factors 3 and 5. The greatest common factor of numerator and denominator is 75. Given that both numerator and denominator have only 7 factors, find this number

25 out of 75

If the power of a + AB = 20, the power of ab-b = - 13. (1) find the power of a + the power of 2ab-b; (2) find the power of a + the power of 3ab-2b

And this is where we want to analyze a-178; (AB = 20ab-b (AB-Ab = 20ab-ab-ab-b; (AB-Ab = 20ab-ab-b; (AB-Ab = 20ab-b; 178; = -13 (1) a (1) a-b-b; (; (; (2a b-b-b-b; 178; (; (AB-Ab) + (ab-b-b; (ab-ab-b; (ab-ab-b; (ab-ab-ab-b; (ab-ab-ab-ab-ab-ab-b; (ab-ab-ab-ab-ab-ab-ab-b; (; (ab-ab-ab-ab-ab-ab-ab; (ab-ab-ab-ab; (ab-ab-ab-ab-ab; (ab-ab-ab-ab-ab-ab-ab-ab; (ab-ab-ab-ab; (ab-ab-ab-ab-ab-ab-ab-ab-ab-178; (ab-ab-ab-ab-ab-ab-ab-ab-ab-ab 20-26 = - 6

It is known that for any real number x, if f (- x) = - f (x), G (- x) = g (x), and x > 0, then x0, G '(x) > 0, B F' (x) > 0, G '(x)

F (- x) = - f (x) is an odd function. When x > 0, f '(x) > 0, when x0, when x

I bought (03 05 07 13 14) 06 08 09 10 11 12 15 16 17 18 19 20 21
Is it the second prize in the competition?
I bought 03 05 07 13 14) 06 08 09 10 11 12 15 16 17 18 19 20 21 22 24:10
Is it the second prize in the competition?
The number above is wrong. This is right

It's not the second prize. It's the fifth prize with three notes. It's 30 yuan
03 05 07 13 14 these red numbers are fixed, the remaining one is optional from 06 08 09 10 11 12 15 17 18 19 20 21 22 24 as a supplement, and the blue number is 10. Among the five fixed numbers, 05.07.13 is consistent with the winning number, and then choose any one from (06.12.18), They are (03.05.06.07.13.14): 10 (03.05.07.12.13.14): 10 (03.05.07.13.14): 10 (03.05.07.13.14.18): 10
So it is 3 note 5 prize, the bonus is 30 yuan!
Dare to gamble
In 33 red ball numbers, choose 1-5 numbers as the courage code of each bet, and then add other different red ball numbers as the drag code to bet. There is no courage code or drag code in basketball. The maximum bonus of single bet can reach 10 million yuan
I don't know if I'm right. I just studied lottery recently!

The difference between 1 and the reciprocal of a number is three fifths. This number is 2.5. How do you calculate it?

1-3/5=2/5
The reciprocal of 2 / 5 is 5 / 2, which is 2.5

First simplify and then evaluate the square of - 2 (2x + y) - half (2x + y) + the square of 3 (2x + y) + (y + 2x) - 5, where x = 1, y = 2

The title is a little unclear, I don't know if it is like this - 2 (2x + y) ^ 2 - (2x + y) / 2 + 3 (2x + y) ^ 2 + (2x + y) - 5 = (2x + y) ^ 2 + (2x + y) / 2-5 = (2x + y + 1 / 4) ^ 2-5-1 / 16 = (4 + 1 / 4) ^ 2-5-1 / 16 = (17 / 4) ^ 2-5-1 / 16 = 289 / 16-81 / 16 = 208 / 16 = 13

What can be easily calculated is 5 / 12 + 5 / 9 + 7 / 12 + 4 / 9

5/12+5/9+7/12+4/9
=（5/12+7/12）+（5/9+4/9）
=1+1
=2
I wish you a happy study!