It is known that the square of M + 2 = 0 of (M + 1) x is a linear equation of one variable with respect to X

It is known that the square of M + 2 = 0 of (M + 1) x is a linear equation of one variable with respect to X

It is known that the square of M + 2 = 0 of (M + 1) x is a linear equation of one variable with respect to X
So M & # 178; = 1;
m+1≠0;
So m = 1;
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Use "dichotomy" to find the root of equation x & # 179; - x-3 = 0 in interval (1,2), take the midpoint of interval x0 = 1.5, then the next interval with root is

The interval is (1.5,2)
Because x = 1.5, equation 0

If the power 0 of (x + 2) is 1, then the value range of X is

The base number cannot be zero, so we can get the following result:
The solution of X + 2 ≠ 0 is x ≠ - 2

Let f '' (x) exist, find the second order function d ^ 2Y / DX ^ 2 of the following function: (1) y = f (x ^ 2)

dy/dx = 2xf'(x^2)
d^2y/dx^2 = d(2xf'(x^2))/dx = 2f'(x^2) + 4x^2f''(x^2)
These are just the derivative formula of compound function, LZ should be able to work out by itself

Three math problems (solving one of them is OK)
1. Given x + y = 5, X & sup2; + Y & sup2; = 13, find the value of the algebraic formula X & sup3; y + 2x & sup2; Y & sup2; + XY & sup3
2. Given X & sup2; + 2x + Y & sup2; - 6y + 10 = 0, find the value of X to the power of Y
3. Given x (x-1) - (X & sup2; - y) + 2 = 0, find the value of the algebraic formula X & sup2; + Y & sup2. / 2-xy

1. Solve the system of two equations
x=2,y=3
or
x=3,y=2
So there are:
（1）x³y+2x²y²+xy³=24+72+54=150
（2）x³y+2x²y²+xy³=54+72+24=150
That is, the result is 150
Solution 2: X & sup3; y + 2x & sup2; Y & sup2; + XY & sup3; = XY (x + y) ^ 2 = {[(x + y) ^ 2 - (X & sup2; + Y & sup2;)] / 2} (x + y) ^ 2 = {[5 ^ 2-13] / 2} * 5 ^ 2 = 150
2.x²+2x+y²-6y+10=(x+1)^2+(y-3)^2=0
So, x = - 1, y = 3
Yes, x ^ y = - 1
3.x（x-1）-（x²-y）+2=y-x+2=0
This shows that X-Y = 2
x²+y²/2-xy=(x-y)^2/2=2

Y = xsinx + xarctane ^ x, find the derivative of Y

Y = xsinx + xarctan (e ^ x), we can use derivative multiplication rule + chain rule
dy/dx=(sinx+xcosx)+arctan(e^x)+x*1/[1+(e^x)²]*d(e^x)/dx
=sinx+xcosx+arctan(e^x)+(xe^x)/[1+e^(2x)]

The decimal addition and subtraction method needs answers
30 questions

1.2+2.8=41.5+3.6=5.122.5+23=45.50.125+0.348=0.4730.65+2.35=34.27+3.15=7.423.24+1.157+0.163=4.540.12+3.16=3.280.124+3.15=3.27422.26+3.16=25.420.14+10.46=10.61.238+0.152=1.394.12+5.18=9.310.56+12.44=231...

If the algebraic formula ax ^ 5 + BX & sup3; + cx-5, when x = - 2, the value is 7, then when x = 2, the value of the formula is 7

When x = - 2
ax^5+bx³+cx-5=-128a-8b-2c-5=7
128a+8b+2c=-12
When x = 2
ax^5+bx³+cx-5
=128a+8b+2c-5
=-12-5
=-17

0123456789 can be composed of how many four digits, the number can not be repeated, can not start with 0. It is best to say the method or verification method

If the first one is not zero, there are nine choices from 1 to 9,
In order not to repeat the first one, the second one can include 0 or 9
The third eight
The fourth seven
9 × 9 × 8 × 7 = 4536 species,

If the asymptote equation of hyperbola is y = 1 / 2, then it is equal to

Hyperbola
x²/4-y²/b²=1
Find asymptote, let
x²/4-y²/b=0
x/2=±y/b
y=±b/2x
b/2=1/2
b=1