Given that the m power of a is 2, the 2n power of B is 3, and the 3Q power of C is 4, find the 2m power of a × the 6N power of B △ the 9q power of C

Given that the m power of a is 2, the 2n power of B is 3, and the 3Q power of C is 4, find the 2m power of a × the 6N power of B △ the 9q power of C

2m power of a × 6N power of B △ 9q power of C
=(m power of a) & # 178; × (2n power of B) & # 179; △ 2q power of C) & # 179;
=2²×3³÷4³
=4×27÷64
=27/16

The line passing through point (1,1) intersects the circle with radius 3 and center (2,3) at two points AB, and the minimum absolute value of AB is calculated

What is the distance between (1,1) and (2,3)
Radical (4 + 1) = radical 5
When the center of the circle is perpendicular to the point (1,1) and AB, AB is the shortest
That is, the absolute value of AB is the smallest
In this case, according to Pythagorean theorem, there is a
AB / 2 = radical (3 & sup2; - 5) = 2
AB=4
The minimum absolute value of AB is 4

Given the function f (x) = 2-x2, G (x) = X. if f (x) * g (x) = min {f (x), G (x)}, then the maximum value of F (x) * g (x) is______ (Note: Min is the minimum value)

According to the meaning of the question, we can make a function image that meets the conditions, such as f (x) * g (x) = 2 − x2 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X ≤ − 2x & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; - 2 − x2 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X ≥ 1 x ＜ 1, which is known from the image, and the maximum value is 1

The monotone decreasing interval of the absolute value (x-1) of function y = x * is

When x > = 1
Then: y = x (x-1) = (x - (1 / 2)) ^ 2 - (1 / 4)
Because X - (1 / 2) > 0
So, the function increases monotonically
When X1 / 2, the function decreases monotonically
The monotone decreasing interval is: (0.5,1)

Let a function defined on R satisfy f (x) * f (x + 2) = 13, if f (1) = 2, then f (99)=

f(x)f(x+2)=13
therefore
f(x+2)=13/f(x)
f(1)=2
f(3)=13/f(1)=6.5
f(5)=13/f(3)=2
f(7)=13/f(5)=6.5
therefore
f(99)=6.5

Let a be a symmetric matrix and | a ≠ 0, it is proved that a ^ - 1 is also a symmetric matrix

Because | a | = | a ^ t ≠ 0
So a ^ t is reversible
A^-1=(A^T)^-1=(A^-1)^T
So a ^ - 1 is a symmetric matrix

Is the subject when and where, the predicate singular or plural? Why?

In a sentence that starts with when and where, the real subject is the component after the auxiliary verb (or modal verb or be verb) after when and where. Therefore, whether the predicate verb is singular or plural depends on the component after the auxiliary verb (or modal verb or be verb), that is, the subject
When and where does he join the young pioneers where.when And where is an adverb, used as adverbial of time and place respectively
When and where were they playing games

Prove: (ABC + BCD + CDA + DAB) ^ 2 - (AB CD) (BC DA) (CA BD) = ABCD (a + B + C + D) ^ 2

You just spread both sides into polynomials

Is the predicate verb of the Olympic Games singular or plural?
As the title!
I think it's a whole, so I use singular, but I think the last word is plural. I want to ask whether it's singular or plural

If you only refer to the Olympic Games, use the singular, if you say the event, use the plural

Given that ABC is the length of three sides of triangle ABC, and satisfies a ^ 2 + B ^ 2 + C ^ 2 = AB + BC + AC, try to judge the shape of ABC

a^2+b^2+c^2=ab+bc+ac
Both sides of the equation multiply by 2
2a^2+2b^2+2c^2=2ab+2bc+2ac
2a^2+2b^2+2c^2-2ab-2bc-2ac=0
(a^2-2ab+b^2)+(b^2-2bc+c^2)+(c^2-2ac+a^2)=0
(a-b)^2+(b-c)^2+(c-a)^2=0
therefore
a=b,b=c,c=a
The triangle ABC is an equilateral triangle