Finding the value range of independent variable of inverse proportion function

Finding the value range of independent variable of inverse proportion function

If there are no special requirements for a function, it is generally all real numbers. If there are special requirements, the point where the maximum and minimum values of the function are obtained according to the specific conditions is the value range of the independent variable
If there is no special requirement for the inverse proportion function, it is generally x ≠ 0. If there is a special requirement, the value range of the independent variable can be calculated according to the specific situation

Value range of independent variable of inverse proportion function
Like the title,

In general, the value range of independent variable x is all real numbers with X ≠ 0
For example, if y = K / X-2, then x_____ .
A: because X-2 ≠ 0, X ≠ 2

We know the functions y = 2x and y = KX + 1 (K ≠ 0). (1) if the images of the two functions pass through the points (1, a), we can find the values of a and K; (2) when k takes any value, the images of the two functions always have a common point

(1) ∵ the images of the two functions pass through points (1, a), ∵ a = 21a = K + 1. ∵ a = 2K = 1. (2) substituting y = 2x into y = KX + 1, eliminating y. we get kx2 + X-2 = 0. ∵ K ≠ o, ∵ if we want to make the images of the two functions have common points, we only need △≥ 0. ∵ a = b2-4ac = 1 + 8K ≥ 0, the solution is k ≥ - 18; ∵ K ≥ - 18 and K ≠ 0

Solving equation 65 + x = 15 + X + 13 + X + 9 + X

65+x=15+x+13+x+9+x
65+x=37+3x
2x=28
x=14

If A1 = 100 + (- 6) * 1, A2 = 100 + (- 6) * 2, A3 = 100 + (- 6) * 3,
Then an =? When an = 2002, n =?

Because: n = the last number multiplied, let the last number be x, and we can get the formula:
100+（-6）*x=2002
-6x=2002-100
x=317

√1/2 + √1/3=?√64/9 X144/169=?√X² - 14X + 49=X - 7

√1/2 + √1/3=
=√2/2+√3/3
=（3√2+2√3)/6
√64/9 X144/169
=√(8²×4²/13²)
=8×4/13
=32/13
√X² - 14X + 49=X - 7
√(X-7)²=|X-7|=X-7
X-7≥0
X≥7

Lingo solution min = X1 ^ 2 + X1 * x2 + x2 ^ 2-60 * x1-3 * x2; wrong result
Objective value:-900.0 In this case, X1 = 30.0, X2 = 0.0
But when X1 and X2 are 39 and - 18 respectively, the minimum value is - 1143
What's going on?
And when changing the X2 coefficient, the result is the same: that is to change - 3 to 3, 5, 6, 7 It's all the same

Fu = [x (1). ^ 2 + X (1). * x (2) + X (2). ^ 2-60 * x (1) - 3 * x (2) '; x0 = [30,0]; [x, favl] = fminsearch (Fu, x0) this is the code of MATLAB, and the result is (39 - 18) as for your lingo, because lingo default all variables are non negative, the result X2 is 0, you add @ free (x2)

If 4A ^ 2 + Ma + 9 is a complete square, then the value of the constant M is ()

m=±12.

2. The radius of ball o is equal to 8, circle m and circle n are the two small circles of the ball, AB is the common chord of the two small circles, if om = on = Mn = 6, find ab

Let the midpoint of AB be C, connecting OC and MC. Since OM is perpendicular to the plane of Wang Yuan m, the angle OMC is a right angle
Because om = on = Mn = 6, the angle MOC = 30 degrees, OC = OM / cos30 = 6 / (√ 3 / 2) = 4 √ 3
Connecting OA, in the RT triangle OCA, OA = 8, AC = √ (OA ^ 2-oc ^ 2) = 4. So, ab = 8

How to calculate the - 1 power, - 2 power, - 3 power, - 4 power, - 5 power of (a + b)?

It's 1 / 1 of (a + b), 1 / 2 of (a + b) and 1 / 3 of (a + b)