Find the range of function y = x2-2x + 2, X ∈ (0,3]

Find the range of function y = x2-2x + 2, X ∈ (0,3]


The range of y = (x-1) ^ 2 + 1 [1,5]



Finding the range of function y = (2x + 1) / x2


yx²=2x+1
yx²-2x-1=0
X is a real number, so the equation has a solution
The discriminant is greater than or equal to 0
4+4y>=0
y>=-1
Range [- 1, + ∞)



Let f (x) be a differentiable function and △ X be the increment of the independent variable at x, then Lim △ x → 0 F2 (x + △ x) - F2 (x)=
^
Let f (x) be a differentiable function and △ X be the increment of the independent variable at x, then Lim △ x → 0 {[F2 (x + △ x) - F2 (x)] \ △ x}=
2 is the square


lim△x→0{【f²(x+△x)-f²(x)】\△x}=lim△x→0【f(x+△x)+f(x)】{【f(x+△x)-f(x)】\△x}=2f(x)·f'(x)



At the end of last year, an enterprise issued a total of 20 million yuan year-end bonus to all 800 employees. The enterprise plans to increase the annual bonus by 600000 yuan in 10 years from this year, which is a net increase of a employees every year. (1) if a = 9, will the enterprise's per capita year-end bonus exceed 30000 yuan in the planned time? (2) In order to increase the per capita year-end bonus year by year, how many employees can the net increase of the enterprise each year not exceed?


(1) Suppose that in the first year of this year, the annual bonus per capita of the enterprise is y 10000 yuan, then y = 2000 + 60x800 + ax (x ∈ n *, 1 ≤ x ≤ 10); (4 points) from the question meaning, there is 2000 + 60x800 + 9x ≥ 3, the solution is x ≥ 40033 > 10



When the side length of a small square increases by 8 cm, the area increases by 224 square cm. How much is the side length of a small square


Let the side length of a small square be x cm
8x+8x+8×8=224
16x=160
x=10
A: the side length of the small square is 10 cm



Yang Guang knew that the round spot in the shade was the sun on the ground through the small holes between the leaves
Yang Guang knows that the round spot in the shade is the image of the sun on the ground through the small holes between the leaves. He measured that the diameter of the spot is 7cm, and the distance between the spot and the small hole is 7.5m. According to the book, the distance between the sun and the earth is 1.5 times 10 to the 11th Power M, from which the diameter of the sun can be estimated to be____ m


Set to X
0.07M/7.5M=X/150000000000
X=3500000000000



What is the physical meaning of self weight stress and additional stress in soil, and what are the characteristics of their distribution along the depth


Stress belongs to the concept of physics, there is no physical meaning
You can say the concept of self weight stress and additional stress
Gravity stress, as the name suggests, refers to the stress produced by the gravity of soil at a certain position, which can be either the inside or the edge of soil
Additional stress refers to the stress in or around the soil caused by external load
In a given soil mass, the self weight stress increases linearly
However, the additional stress decays in a certain trend, which is caused by stress diffusion
The reason why the self weight stress does not appear stress diffusion is that the self weight always exists in the interior of the object, while the additional load exists in the exterior of the object. These two kinds of forces are different in dimension and action position. Therefore, the force effect is also different



It is known that the perimeter of a square is cm and the area is the square of SCM
1. Find the functional relationship between S and C
2. When s = 1 square centimeter, find the side length of the square
3. When C takes what value, s ≥ 4 square centimeter
For details. Thank you


Let the side length be X
C=4X,X*X=S
S=1,X=1
C=4cm
X*X≥4
Then x ≥ 2
C≥8



A simple algorithm of 47 out of 73 times 67 plus 26 times 67 out of 73


=(47*67)/73+(26*67)/73
=(67/73)*(47+26)
=(67/73)*73
=67



Given that f (x) = a + 1 / A ^ x + 1 is an odd function, find the value of a and the range of F (x)


For odd functions on R, f (0) = 0
So a + 1 / 2 = 0, a = - 1 / 2
f(x)= -1/2+1/(( -1/2)^x+1)
∵( -1/2)^x>0,( -1/2)^x+1>1,
∴0