Let f (x) = {- 2x + 1,4x - 5} max, then the minimum value of the function is

Let f (x) = {- 2x + 1,4x - 5} max, then the minimum value of the function is

(4x-5)-(-2x+1)=6(x-1)
When x > = 1, then: 4x-5 > = - 2x + 1
f(x)=4x-5>=4-5=-1
When x

If f (x) is a linear function and 2F (1) + 3f (2) = 3, 2f (- 1) - f (0) = - 1, then f (x) is equal to ()
A. 4x9+y9B. 36x-9C. 4x9−19D. 9-36x

Let f (x) = ax + B, then 2 (a + b) + 3 (2a + b) = 32 (− a + b) − B = − 1, then 8A + 5B = 3 − 2A + B = − 1, a = 49b = − 19, so f (x) = 49x − 19, so choose C

The known set a = {x | X & # 178; + 2x-3 ≤ 0}, B = {x | 3 / (x + 1) ≥ 1}, C = {x | (x + m + 4) (x-m + 4 ≤ 0, M > 0}
If a ∩ C ≠ empty set, find the value range of real number M

(x + 3) (x-1) ≤ 0, so a = {- 3 ≤ x ≤ 1}, [x + (4 + m)] [x + (4-m)] ≤ 0, M > 0, so
C = {- (4 + m) ≤ x ≤ - (4-m)} if a ∩ C ≠ empty set, then - 3 ≤ - (4 + m) ≤ 1 or - 3 ≤ - (4-m) ≤ 1,
-5 ≤ m ≤ - 1 or 1 ≤ m ≤ 5

The image of a certain function passes through points (1, - 2), and the value of function y decreases with the increase of independent variable x. please write a functional relation satisfying the above conditions______ ．

∵ y decreases with the increase of X, ∵ K ＜ 0. And ∵ the line passes through the point (1, - 2), ∵ the analytic formula can be: y = - X-1, etc. so the answer is: y = - X-1, etc

2.6 is the solution of the equation x + 2.8 = 6.4

2.6 is the solution of the equation x + 2.8 = 6.4
x+2.8=6.4
x=6.4-2.8
x=3.6

The elliptic equation with the same focus as the ellipse 9x2 + 4y2 = 36 and the minor axis length of 45 is______ ．

Ellipse 9x2 + 4y2 = 36, C = 5, the focus of ellipse is the same as that of ellipse 9x2 + 4y2 = 36, the half focal length of ellipse is C = 5, that is, A2-B2 = 5, the length of minor axis is 45, B = 25, a = 5, the standard equation of ellipse is y225 + x220 = 1, so the answer is y225 + x220 = 1

Solving equation 360 / (X-6) - 360 / x = 10

If both sides multiply x (X-6), 360x-360 (X-6) = 10 · x (X-6) 360x-360x + 2160 = 10x & # 178; - 60x 10x & # 178; - 60x = 2160 X & # 178; - 6x = 216

What is 4sin α cos α equal to

According to the double angle formula, if 2Sin α cos α = sin2 α, then the original formula = 2sin2 α

Positional relationship between straight line and circle (15 17:24:27)
Given the circle C: x2 + y2-2x + 4y-4 = 0, is there a straight line L with a slope of 1, so that the circle with the diameter of the chord AB cut by the circle C passes through the origin? If there is, write the equation of the straight line L; if not, explain the reason

x²+y²-2x+4y-4=0
(x-1) & sup2; + (y + 2) & sup2; = 9, so r = 3, Center (1, - 2)
The line passes through the center of the circle (because it is the diameter) and the origin
So let y = x + B, substituting (1, - 2) and (0,0) into the solution, B is not equal
So there is no such line

There are several different ways to fill in the integer of 12 + () + () = 12 to make the equation hold

There are countless different ways of filling
12+(0)+(0)=12
12+(-1)+(1)=12
12+(-2)+(2)=12
12+(-3)+(3)=12
12+(-4)+(4)=12
12+(-5)+(5)=12
12+(-6)+(6)=12
12+(-7)+(7)=12
······
Just fill in a pair of opposite numbers