∫, # 185; (1-x & # 178;) ∫ (2 / 3) DX 0 by substitution, ∫¹（1-x²）∧(2/3)dx 0

∫, # 185; (1-x & # 178;) ∫ (2 / 3) DX 0 by substitution, ∫¹（1-x²）∧(2/3)dx 0

∫ [0-- > 1] (1-x ^ 2) ^ (3 / 2) DX let x = sinu, then DX = cosudu, X: 0-- > 1, u: 0--π / 2, then all trigonometric functions are positive, (1-x ^ 2) ^ (3 / 2) = (COSU) ^ 3 * COSU Du = ∫ [0--π / 2] (COSU) ^ 4 Du = ∫ [0--π / 2] (1 / 2 (1 + C

∫x/(x^4+2(x^2)+5)dx

The original formula is 1 / 2 * \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\* a

120% X - 11 / 12x = 6.5
11 / 12 = 11 / 12

120％x - 11/12x = 6.5
6/5x-11/12x=6.5
72x-55x=6.5*5*12
17x=390
x=390/17

If the sum of the first n terms of the equal ratio sequence {an} is Sn, and A2 = 1-a1, A4 = 9-a3, then what is A4 + A5 equal to?

A2 + A1 = 1, in duplicate
A 4 + a 3 = 9
We can get the result by subtracting the original form from the second form
2d+2d=8 d=2
A 5 + a 4 = X
Three minus two
d+d=x-9
d=2
x=13

How to solve the equation of 9.4 × 6.5-14x = 49.9?
Be quick! It will be handed in soon!

61.1-14x=49.9
14x=61.1-49.9
14x=11.2
X = 11.2 divided by 14
x=0.8

j avascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=20

j avascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=200; x5=300; y5=200; DI= document.images ; DIL= DI.length ; function A(){for(i=0; i-DIL; i++){DIS=DI[ i ].style; DIS.position= 'abs...

Given the quadratic trinomial X & # 178; 3-6x + 5 (1), when x is what value, the value of the quadratic trinomial is equal to x + 4?

To solve the equation:
x²-6x+5 = x+4 ,
x²-7x+1 = 0 ,
(x-7/2)² = (7/2)²-1 = 45/4 ,
x = (1/2)(7±3√5) ,
Therefore, when x = (1 / 2) (7 ± 3 √ 5), the value of this quadratic trinomial is equal to x + 4

As shown in the figure, AC is the diameter of ⊙ o, ob ⊥ AC, and the chord BN intersects AC at point M. if OC = 3, OM = 1, then Mn=______ ．

∵ AC is the diameter of ⊙ o, ob ⊥ AC, the intersection of chord BN, AC at points m.oc = 3, OM = 1, ∵ ob = 3, BM = 3 + 1 = 2, let Mn = x, ∵ cm · am = BM · Mn, ∵ 3 + 1) (3 − 1) = 2x, ∵ x = 1, that is Mn = 1

M power of 16 △ M-1 power of 8 = 11 power of 4 = 512, M =?

The m-th power of 16 is equal to the m-th power of 8
=M power of the fourth power of 2 △ M-1 power of the third power of 2
=4 m power of 2 △ 3 (m-1) power of 2
=4m-3 (m-1) power of 2
=M + 3 power of 2
4 to the 11th power = 2 & # 178; to the 11th power
=The 22nd power of 2
So m + 3 = 22 and M = 19
Wrong title:
512 = 9 power of 2 ≠ 11 power of 4

An electric energy meter marked with "220 V & nbsp; 5A" can be used at maximum power______ When the 120 Watt refrigerator, 100 watt TV and 750 watt microwave oven are all working, they can light up at most______ A "220 V & amp; 60 W" lamp

(1) The maximum power of household electric appliances is: P = UI = 220V × 5A = 1100W. (2) the total power of the household circuit that can be connected to the bulb is: P lamp total = 1100w-120w-100w-750w = 130W, and P lamp = 60W, then the number of bulbs is: n = P lamp total P lamp = 130w60w ≈ 2.2, so it can light up to two bulbs