As shown in the figure, the circumscribed circle diameter ab of △ ADC intersects CD at point e. it is known that ∠ C = 65 ° and ∠ d = 47 ° and the degree of ∠ CEB is calculated

Connecting BC, ∵ AB is the diameter of the circle, ∵ ACB = 90 °, ∵ C = 65 °, ∵ BCD = 90 ° - C = 90 ° - 65 ° = 25 °, ∵ d = 47 °, ∵ ABC = ∵ d = 47 °, in △ BCE, ∵ CEB = 180 ° - BCD -

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