When m takes what value, the quadratic equation of one variable x ^ 2 + (2m + 1) x + (m-2) ^ 2 = 0 (1) There are two unequal real roots (2) There are two equal real roots (3) There is no real root

When m takes what value, the quadratic equation of one variable x ^ 2 + (2m + 1) x + (m-2) ^ 2 = 0 (1) There are two unequal real roots (2) There are two equal real roots (3) There is no real root

X ^ 2 + (2m + 1) x + (m-2) ^ 2 = 0, Δ = (2m + 1) & # 178; - 4 (m-2) & # 178; = 20m-15 (1) when Δ = 20m-15 ＞ 0, i.e. m ＞ 3 / 4, there are two unequal real roots (2) when Δ = 20m-15 = 0, i.e. M = 3 / 4, there are two equal real roots (3) when Δ = 20m-15 ＜ 0, i.e. m ＜ 3 / 4, there is no real number

Given that the equation 2mxm + 2 + 4 = 7 is a linear equation of one variable with respect to x, then M=______ ．

∵ the original equation is a linear equation with one variable, ∵ m + 2 = 1, and 2m ≠ 0, the solution is m = - 1

Solving equation (96 / x ^ 2) + (3x-1 / 4-x) = (2x-1 / x + 4) - 5

The original equation becomes 96 / x ^ = (2x-1) / (x + 4) + (3x-1) / (x-4) - 5 = [(2x-1) (x-4) + (3x-1) (x + 4)] / (x ^ - 16) - 52X ^ - 9x + 43x ^ + 11x-4___________ 5x ^ + 2x, it becomes 96 / x ^ = (2x + 80) / (x ^ - 16), ｜ 48 (x ^ - 16) = (x + 40) x ^, x ^ 3-8x ^ + 768 = 0, please check the question

Solve the equation (x + 1) = (1-3x) and | 2x + 1 | = | x-3 |, find x =?, | 2x-1 |, | 1-y | = 2, find x + y =?
The sooner the better. It's due tomorrow

|x+1|=|1-3x|
[(x+1)+(1-3x)][(x+1)-(1-3x)]=0
x1=1,x2=0
|2x+1|=|x-3|
[(2x+1)+(x-3)][(2x+1)-(x-3)]=0
x1=2/3,x2=-4
|2x-1|+|1-y|=2
2x-1=0
1-y=0
x=1/2,y=1
x+y=3/2

The dimension of the linear space formed by the addition and multiplication of all real symmetric matrices of order 3 is? Why is the answer 6?

Expressed as:
abc
bde
cef
Only 6 numbers are changing. Let one number be 1 and the others be 0, then we can get the base, which is composed of 6 matrices

The relationship between line and plane
It is known that DP is a point out of the plane of the parallelogram ABCD, M is the midpoint of PC, take a point G on DM, pass through point G and AP to make the plane intersection, BDM at GH, and prove AP ‖ GH

It's too difficult. It's better to draw a good graph. You'd better refer to the kilometer and theorem yourself and do it. You can consult the teacher. Don't forget

Definite integral (0 to π) of SiNx 4 power
 

English translation
This is from some background materials of last week's Obama speech. I understand the meaning, but it's awkward to translate it into Chinese
For a decade,America has been spending more money than we’ve taken in.For several decades,our debt has been rising.And let’s be honest – neither party in this town is blameless.

It's about two numbers. The number a is three times more than the number B, the number B is three times less than the number a, the number B is two
It's better to have a solution

Let a be x and B be y, then
x=3y+2 ①
y=3x-2 ②
Substituting (2) into (1) leads to (3)
x=3(3x-2)+2
It is found that x = 1 / 2
Substituting into 2, we get y = - 1 / 2
This kind of problem, is two unknowns, respectively list the relationship, and then sort out the relationship of one of the unknowns, into the other on it

Area formula of rectangle
Except s = ab

The area of the rectangle = the diagonal multiplied by the height of the bottom of the diagonal