-1, - 3, - 5, - 7, - 9,2,4,6,8, fill in the lattice of 3 * 3, so that the product of three numbers is negative, and the sum of absolute values of three numbers is equal

-1, - 3, - 5, - 7, - 9,2,4,6,8, fill in the lattice of 3 * 3, so that the product of three numbers is negative, and the sum of absolute values of three numbers is equal

2 －9 4
－7 －5 －3
6 －1 8

Let f (x) = asin (KX - π / 3) and G (x) = bcos (2kx - π / 6), (a > 0, b > 0, k > o) be the sum of their minimum positive periods
Let (3 π) / 2, f (π / 2) = g (π / 2), f (π / 4) = - √ 3G (π / 4) - 1

T1 + T2 = 2 π / | K | + 2 π / | 2K | = 3 π / k = 3 π / 2K = 2F (x) = asin (2x - π / 3) g (x) = bcos (4x - π / 6) f (π / 2) = asin (2 π / 3) = asin (π - π / 3) = ACOS (π / 2 - π / 6) = ACOS (π / 6) = g (π / 2) = bcos (- π / 6) = bcos (π / 6) so a = BF (π / 4) = asin (π / 6)

Absolute value of solutions and linear equation of one variable
(1)/2X-1/+/x-2/=/x+1/
(2)//3x-5/+4/=8
(3)/x-/2x+1//=3
// represents the absolute value sign

The best way to solve the absolute value equation is: let the formula in each absolute value sign be zero, draw its position on the number axis, and then divide the case solution
Let each absolute value be zero, x = 1 / 2, x = 2, x = - 1
Draw: -- (- 1) --- 0 --- 1 / 2 --- 2----
(1) X > = 2, all positive, 2x-1 + X-2 = x + 1 = > x = 2
（2）1/2

What is the domain of the inverse function of the function f (x) = 3 ^ x + SiNx, X ∈ [0,1]?

The domain of inverse function is the domain of original function. This function is a monotone increasing function on [0,1], so the domain of inverse function is [1,3 + sin1], so the domain of inverse function is it

The derivative is one tenth of SiNx. What is the original function

ln|cscx-cotx|+C=ln|(1-cosx)/sinx|+C

It is proved that the function f (x) = 4x2 + 3 is an increasing function in the interval (0, + 00)

There are many ways to do it, and we'll use derivative to prove it
y'=8x
When x > 0, y '> 0, so the function is an increasing function on (0, + ∞)

A is an orthogonal matrix of order n. It is proved that the adjoint of a is also an orthogonal matrix

Is has the plural of have
What's the plural of have

Have is a verb. There is no singular or plural form in a verb. But the subject in front of a verb can be singular or plural. Have is used after the plural subject and the first or second person subject, and has is used after the third person subject

First simplify, then evaluate: 1 / 3 (- 3ax ^ - ax ^ + 3) - [- ax ^ - 2 / 3ax-1]. Where a = 2. X = 3

1/3（-3ax^-ax+3)-[-ax^-2/3ax-1]
=-ax²-1/3ax+1+ax²+2/3ax+1
=1 / 3ax + 2, where a = 2. X = 3
=1/3*2*3+2
=2+2
=4

Can we add an uncountable noun after a number of?

A number of students are fond of music.the The number of the students in our class is large