How to solve the equation of 8x-4 (15-x) = 72

How to solve the equation of 8x-4 (15-x) = 72

8X-4(15-X)=72
8x-60+4x=72
12x=72+60=132
x=132/12=11

15-8x=1.
We must be complete and make it clear one by one. Today we are going to,

15-1.4=8X
13.6=8X
X=1.7

Four Thirds x × 50% = 17.4 this should be the solution of the equation!

Four Thirds x 50% = 17.4
4X / 3 * 1 / 2 = 17.4
2X = 17.4
X = 17.4 △ 2 / 3
x=26.1
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9 (x + 3) = 8 (x + 4)

9x+27=8x+32
9x-8x=32-27
x=5

Talking about the use of NaCl in life by using chemical knowledge and life practice (at least four points)
Five is better

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2. Medical normal saline
3. Chlor alkali industry
4. Raw materials for Hou's soda process
5. Pickled vegetables

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How can X & # 178; + 6x + 9 be simplified to (x + 3) &# 178?

X & # 178; + 3x + 3x + 9 = x (x + 3) + 3 (x + 3), extract the common factor (x + 3), (x + 3) (x + 3), get (x + 3) &# 178;, just remember

As shown in the figure, the voltage at both ends of the power supply remains unchanged. When the switches s and S2 are closed and S1 and S3 are open, the voltage representation number is U1, the current representation number is I1, and the sum of electric power of resistance R2 and R3 is 28w. When the switches s, S1 and S3 are closed and S2 is open, the voltage representation number is U2, the current representation number is I2, and the sum of electric power of resistance R1 and R3 is 72W (1) The current represents the ratio of I1 to I2. (2) the resistance of R3. (3) the voltage u at both ends of the power supply

When the switches s and S2 are closed and S1 and S3 are open, the three resistors are connected in series, and the circuit is shown in Figure a. the voltmeter measures the voltage U1 at both ends of resistance R2 and R3, and the ammeter measures the circuit current I1; when the switches s, S1 and S3 are closed and S2 is open, R1 and R3 are connected in series, and the circuit is shown in Figure B. the voltmeter measures the voltage U2 at both ends of resistance R1 and R3, and the ammeter measures the circuit current I2 sp; (1) According to the title and the circuit diagram, we can get: the sum of electric power of resistance R2 and R3: P = u1i1 = 28w, the sum of electric power of resistance R1 and R3: P ′ = u2i2 = 72W, ∵ U1: U2 = 7:12 ∵ I1: I2 = PP ′: u1u2 = 2872 × 127 = 2:3; (2) (3) according to the two diagrams of Party A and Party B, the power supply voltage is equal to U2, because U1: U2 = 7:12, R1 = 5 Ω, and in the series circuit, the voltage ratio is equal to resistance So (R1 + R2 + R3): (R2 + R3) = U2: U1 = 12:7; that is, R2 + R3 = 7 Ω; from P = u2r, 28w = (712u2) 2r2 + R3 ∵ R2 + R3 = 7 Ω, ∵ U2 = 24 V; and ∵ 72W = u22r1 + R3 = (24 V) 25 Ω + R3 ∵ R3 = 3 Ω; answer: (1) the ratio of I1 to I2 is 2:3. (2) the resistance of R3 is 3 Ω. (3) the voltage at both ends of the power supply is 24 v

When an object moves in a straight line with uniform acceleration, the initial velocity is 10m / s, and the acceleration is 2m / S ^ 2, then: 1. What is the meaning of acceleration 2m / S ^ 2 2, 5S
2. What is the velocity of the object at the end of 5S
3. What is the displacement of the object at the end of 5S

1. It means that the speed of the object increases by 2m / s every second
2. The 5S speed is increased by 5 * 2, so the speed is 10 + 10 = 20 (M / s)
3. S = V (initial) t + 1 / 2 * a * T ^ 2
=10*5 + 1/2*2*5^2
= 50+25
= 75（m）

How to understand the calculation formula of electric power of pure resistance and impure resistance for memory

In the non pure resistance circuit, only w = uit and P = UI can be used, because the consumer is equivalent to a resistance in a power supply string at this time, so u at both ends of the consumer is the voltage sum of the circuit power supply and its own power supply, that is, u is not equal to IR, but everything in the pure resistance circuit is as usual, and P = U2 / R can be used