Given that x = 3 is the solution of the equation x = (x-a) / 2-1, find the inequality (10-A) X

Given that x = 3 is the solution of the equation x = (x-a) / 2-1, find the inequality (10-A) X

The solution substitutes x = 3 into the equation x = (x-a) / 2-1
A = - 5
Then the inequality (10-A) x

Given that x = 4 is the solution of the equation [(x-m) / 2] - 2 = X-1, try to find the inequality [2 - (M / 5)] X

X = 4 generation equation [(x-m) / 2] - 2 = X-1
There are: (4-m) / 2 = 5 m = - 6
Inequality [2 - (M / 5)] x

Given x-3y = 0, find the value of the algebraic formula x ^ 2-4xy + 4xy ^ 2 / 2 x △ x-2y / 2
This is the 16 the first mock exam of mathematics in Fengtai in 2013.

The former part of the division sign of the original algebraic formula can be changed into (x - 2Y) ^ 2 / 2 x, and (x - 2Y) 2 / 2 x, that is to say, 2 (x - 2Y) x, because X - 3Y = 0 (the condition of the original problem has been given), the 3Y movable term to the right of the equal sign

A and B start from a and B at the same time and travel in opposite directions. A travels 50 kilometers per hour and B 40 kilometers per hour. A reaches the midpoint one hour earlier than B. how many hours does a reach the midpoint?

40 × 1 ^ (50-40), = 40 ^ 10, = 4 (hours); answer: a reaches the midpoint in 4 hours

4 divided by (3 points only 2x) equals 5 points only 2, how to solve this equation?

4÷（2x*1/3）=2/5
4÷2x*3=2/5
12÷2x=2/5
2x=12÷2/5
2x=12*5/2
2x=30
x=15
2x/3=4÷2/5
2x/3=4*5/2
2x/3=10
2x=10÷1/3
2x=10*3
2x=30
x=15

Car a and car B start from two places 560 kilometers apart and travel in opposite directions. It is known that the speed ratio of car a and car B is 4:3. After 4 hours, the two cars meet. How many kilometers does car a travel per hour?

560 △ 4 × 44 + 3, = 140 × 47, = 80 km / h; answer: car a travels 80 km / h

If the decimal point of a number is moved one place to the right, the new number is 56.34 larger than the original number, and the original number is___ ．

Answer: the original number is 6.26, so the answer is: 6.26

A bus and a train depart from ab at the same time. When they meet, the bus runs for 120 km. It is known that the speed ratio of the bus and the truck is 3:2. How many km is the distance between AB and ab?

If the freight cars run x km when they meet, then the distance between AB and ab is (120 + x) km
120：x=3:2
x=80
That is, the distance between AB and ab is (120 + x) = 120 + 80 = 200 km

The negation of the proposition "there is a real number x, so that x > 1" is______ ．

According to the special proposition, the negation is the universal proposition: for any real number x, make x ≤ 1; for any real number x, make x ≤ 1; for any real number x, make x ≤ 1;

The two trains leave from a and B at the same time. Car a runs 54 kilometers per hour, 10% slower than car B. after three hours, the two trains travel 75% of the whole journey. How many kilometers are there between a and B?
Please hurry up

Speed of vehicle B = 54 (1-10%) = 60 km / h
Distance between a and B = 3 × (54 + 60) △ 75% = 456km