It is known that there are six integer solutions to the inequality system {x-a > 0 and 3-2x > 0 about X, and the value range of a is obtained

It is known that there are six integer solutions to the inequality system {x-a > 0 and 3-2x > 0 about X, and the value range of a is obtained

Adopt first

It is known that there are only six integer solutions to the inequality system X − a ＞ 03 − 2x ＞ 0, then the value range of a is ()
A. （-∞，-4）B. [-5，-4）C. （-5，+∞）D. (−5，−32)

From the system of inequalities x − a ＞ 03 − 2x ＞ 0, we can get a ＜ x ＜ 32. From the meaning of the title, we can get that the interval (a, 32) contains six integers: - 4, - 3, - 2, - 1, 0, 1,... - 5 ≤ a ＜ - 4, so we choose: B

How many tons of water is 10000 cubic meters of water

10000 tons

What is 4x-x equal to

4x-x=(4-1)x=3x

121.51 - (4.5-3.8) recursive equation calculation

121.51-(4.5-3.8)
=121.51-4.5+3.8
=117.01+3.8
=120.81

Given that the intersection points of the image of the quadratic function y = AX2 + BX + C and the two coordinate axes are (- 1,0) and (0, - 1), respectively, and the vertex is on the right side of the Y axis, then the value range of the real number B is______ ．

Substituting (- 1, 0) and (0, - 1) into the analytic formula, we can get a − B + C = 0C = − 1, A-B = 1, and the vertex is on the right side of the y-axis, a − B = 1 − B2A > 0, then we can get a − B = 1 − B2A > 0, and the solution is: - 1 < B < 0, so the answer is: - 1 < B < 0

4321×1234-4322×1233 7.2×61.3+73.8×2.8
I'm in a hurry
4321 × 1234-4322 × 1233,,,,,, 7.2 × 61.3 + 73.8 × 2.8

4321×1234-4322×1233
=4321×1234-4321×1233-1333
=4321×（1234-1233）-1333
=4321-1333
=2988
7.2×61.3+73.8×2.8
=7.2×61.3+61.3×2.8+12.5×2.8
=61.3×（7.2+2.8）+12.5×8×0.4
=61.3×10+100×0.4
=613+40
=653

The distance from the intersection point of the parabola y = ax, square + C and Y axis to the origin is 3, and it passes through the point (1,5)
If you want a process, the square is quadratic

When y = ax ^ 2 + C and the intersection of Y axis is x = 0, let x = 0, y = C, and know that the distance from the point to the origin is 3, we can know that C = 3 or C = - 3. When C = 3, then y = ax ^ 2 + 3, substitute point (1,5) into, and the solution is 5 = a * 1 ^ 2 + 3 --- > A = 2, that is, y = 2x ^ 2 + 3. When C = - 3, then y = ax ^ 2-3, substitute point (1,5) into, and the solution is

Given that the image of the function y = AX2 and y = x + 4 intersects at two points a and B, if the coordinates of point a are (2,6), the coordinates of point B are obtained

Because a and B are intersections,
So you can take the coordinates of point a to the function y = AX2 and get a = 1.5
So the function is y = 1.5x2 and y = x + 4
When x = 2, y is 6
When x = - 4 / 3, y is 8 / 3

The trajectory equation of a point equidistant from two points a (- 1, 1, 0) and B (2, - 1, - 1) in space is______ ．

Set the point (x, y, z), get from the meaning of the question: (x + 1) 2 + (Y-1) 2 + (z-0) 2 = (X-2) 2 + (y + 1) 2 + (Z + 1) 2. After sorting out the trajectory equation is: 3x-2y-z = 2, so the answer is: 3x-2y-z = 2