500 milliliter water is equal to how many jin? 1 liter diesel is equal to how many jin?

500 milliliter water is equal to how many jin? 1 liter diesel is equal to how many jin?

500 ml water equals 1 jin, 1 liter diesel equals 1.7 Jin

Is one liter of water equal to four Jin of water?

One liter equals one kilogram and two kilos

1. Solve the equation (1) | x-3 | + 5 = 2x + 2 (2) 3 | x + 2 | - 7 = 11 2. Solve the equation | 4x + 3 | = 2x + 9 in two ways
Please, give me some guidance. It's due tomorrow. I won't do it
1. Solve the equation (1) | x-3 | + 5 = 2x + 2 (2) 3 | x + 2 | - 7 = 11
Only these two. Thank you for your reply

1. Solve the equation (1) | x-3 | + 5 = 2x + 2 | x-3 | - 2x = - 3 to the absolute value: when x ≥ 3, x-3-2x = - 3x = 0, which is contradictory to X ≥ 3, when x < 3, 3-x-2x = - 3x = 2, which is consistent with (2) 3 | x + 2 | - 7 = 113 | x + 2 | - 7 = 113 | x + 2 | = 18 | x + 2 | = 6 to the absolute value x + 2 = 6 or x + 2 = - 6x = 4 or x = - 82

It is known that P: - 2 ≤ 1-x − 13 ≤ 2, Q: x2-2x + 1-m2 ≤ 0 (M > 0). If "non-p" is a sufficient and unnecessary condition of "non-Q", the value range of real number m is obtained

Solution − 2 ≤ 1 − x − 13 ≤ 2 leads to: - 2 ≤ x ≤ 10, solution x2-2x + 1-m2 ≤ 0 leads to: 1-m ≤ x ≤ 1 + m; ｜ non-p: x < - 2, or x > 10; non-Q: x < 1-m, or x > 1 + m; ∫ non-p "is a sufficient and unnecessary condition for" non-Q ", that is, non-Q can be obtained from non-p, but non-p can not be obtained from non-Q; ∫ 1-m ≥ - 2, and 1 + m ≤ 10, leads to m ≤ 3; the value range of real number m is (- ∞, 3]

1/16+2/16+3/16+…… +14/16+15/16+14/16+13/16+…… +Simple calculation and explanation of 2 / 16 + 1 / 16

1/16+2/16+3/16+…… +14/16+15/16+14/16+13/16+…… +2/16+1/16=1/16(1+2+3+…… +14+15+14+13+…… +2+1)=1/16(15×8+15×7)=1/16×225=225/161+2+3+…… +13 + 14 + 15, 7 16 plus 1 8, a total of 15 814 + 13 + +2 + 1 head and tail

Through the fixed point P (- 1, - 2), make a straight line intersection parabola with an inclination angle of 45 degrees, y ^ 2 = 2px at two points a and B. If PA, AB and Pb form an equal ratio sequence, find the equation of parabola

Let a (x1, Y1) B (X2, Y2) from the linear and parabolic equations: X1 + x2 = 2 + 2p x1 × x2 = 1y1 + y2 = 2p Y1 × y2 = - 2p because PA × Pb = the square PA of AB, PA × Pb = 8 + 4pab on the same line can be calculated by vector

Solution ratio: three fifths: x = one third: 2 [2] 10.5 times 208 + 208 times one half minus 208

1.3/5 ：x= 1/3 :2
x*1/3=2*3/5
Multiply the left and right sides of the equation by 15
5x=18
x=5/18
2. Original formula = 208 * (10.5 + 0.5-1)
=208*10
=2080

The quadratic function y = - 14x2-x + 3 is formulated as y = a (X-H) 2 + K______ The vertex coordinates of the quadratic function image are______ ．

Y = - 14x2-x + 3 = - 14 (x2 + 4x) + 3 = - 14 (x + 2) 2 + 4, that is, y = - 14 (x + 2) 2 + 4, the vertex (- 2, 4). So the answer is: y = - 14 (x + 2) 2 + 4, (- 2, 4)

How to calculate 7 × 9 + 12 △ 3-2 = 75 7 × 9 + 12 △ 3-2 = 23

(7X9+12)÷(3-2)=75;
(7x9+12)÷3-2=23

The formula 10 - (7-x) &# 178; has a maximum or a minimum, then how much is x, find the detailed process

There is a maximum of 10
(7-x) &# 178; > = 0, so - (7-x) &# 178;