Solving the equation 4 Λ X - (a + 1) × 6 Λ x = (2a Λ 2-A) × 9 Λ x with respect to X

Solving the equation 4 Λ X - (a + 1) × 6 Λ x = (2a Λ 2-A) × 9 Λ x with respect to X

4^x-(a+1)*6^x=2(a^2-a)*9^x
2 ^ 2x - (a + 1) * 2 ^ x * 3 ^ x-2a (A-1) * 3 ^ 2x = 0 is decomposed into:
(2^x-2a*3^x)[2^x+(a-1)*3^x]=0

Solving exponential equation: 9 (x) + 4 (x + 1) = 8x6 (x)
All in brackets are indices
The words are as follows:
The power X of 9 plus the power X + 1 of 4 is equal to the power X of 8 times 6

9 (x) + 4 (x + 1) = 8x6 (x) let 2 (x) = m 3 (x) = NN (2) + 4m (2) = 8mnm = [4 + 2x3 (1 / 2)] n, that is, M is equal to (4 + 2x3 (1 / 2)] n [3 / 2] (x) = 4 + 2x3 (1 / 2) or x = 4-2x3 (1 / 2) x = log1.5 as the base [4 + 2x3 (1 / 2)] () and the square is the general bracket

The equation 9 - | X-2 | - 4 · 3 - | X-2 | - a = 0 of X has real roots if and only if______ ．

The equation 9 - |x-2-4-4-4-4-4-4-4-4-4-4-4-4-4-4-4-4-4-4-4-4t = (t-2-4t = (t-2-2) 2-4-4-2-2 | [(13) |x-2 | [12-12-12-2 -4-4-2-2-2-4, the equation is equivalent to a = t2-4t = (t-2-2) (T-2) 2-2-4-2-2-2-2-2-2-2-2-2-2-2-2-2-4, let the function f (t (T) (let let let f (t (T) (let let let Let f (T) (t (T) = (t-2-2-2-2-2-2-2-2-2-2-2-2-2-2) let let let let if f (T) has a real root, then - 4 ≤ a < 0

Simplification: 91:52:13______ 1 and three quarters: 2.1:4 and two thirds______

91:52:13____ 7:4:1__
1 and three quarters: 2.1:4 and two thirds____ =10:9:20__

When the chord length of the line y = KX + 2 is cut by the circle x square + y square - 4x = 0=

X ^ 2 + y ^ 2-4x = 0 (X-2) ^ 2 + y ^ 2 = 4 circle center (2,0), radius r = 2 distance from circle center to straight line y = KX + 2: D = | 2k-1 * 0 + 2 | / √ (k ^ 2 + (- 1) ^ 2) = 2 | k-1 | / √ (k ^ 2 + 1) d ^ 2 = 4 (k-1) ^ 2 / (k ^ 2 + 1) chord length = 2 √ (R ^ 2-D ^ 2) = 2 √ (4-4 (k-1) ^ 2 / (k ^ 2 + 1)) = 4 √ (1 - (k ^ 2-2k + 1) / (k ^ 2 + 1)) = 4

What is LG20 minus LG2?

lg20-lg2
=lg(20÷2)
=1

X-0.4X=0.54

X-0.4X=0.54
0.6x==0.54
x=0.9

Recursive equation calculation 36 × 17 △ 51

12

Sign of quadratic function
The meaning of every sign of quadratic function and parabola

1. The parabola is an axisymmetric figure. The axis of symmetry is a straight line x = - B / 2A
The only point of intersection between the axis of symmetry and the parabola is the vertex P of the parabola
In particular, when B = 0, the symmetry axis of the parabola is Y-axis (that is, the line x = 0)
2. The parabola has a vertex P whose coordinates are p (- B / 2a, (4ac-b ^ 2) / 4A)
When - B / 2A = 0, P is on the y-axis; when Δ = B ^ 2-4ac = 0, P is on the x-axis
3. The quadratic coefficient a determines the opening direction and size of the parabola
When a > 0, the parabola opens up; when a < 0, the parabola opens down
|The larger a | is, the smaller the opening of the parabola is
4. The position of the axis of symmetry is determined by the coefficient b of the first term and the coefficient a of the second term
When a and B have the same sign (i.e. AB > 0), the symmetry axis is on the left side of the Y axis; because if the symmetry axis is on the left side, the symmetry axis is less than 0, that is - B / 2a0, so B / 2a is less than 0, so a and B have different signs
When a and B have the same sign (i.e. AB > 0), the axis of symmetry is on the left of y-axis; when a and B have different signs (i.e. AB < 0), the axis of symmetry is on the right of y-axis
In fact, B has its own geometric meaning: the value of the slope k of the function analytic formula (first-order function) of the parabolic tangent at the intersection of the parabola and the y-axis. It can be obtained by deriving the quadratic function
5. The constant term C determines the intersection of the parabola and the y-axis
The intersection of parabola and y-axis at (0, c)
6. The number of intersections of parabola and x-axis
When Δ = B ^ 2; - 4ac > 0, the parabola and X axis have two intersections
When Δ = B ^ 2; - 4ac = 0, the parabola and X axis have one intersection
Important concepts: (a, B, C are constants, a ≠ 0, and a determines the opening direction of the function. When a > 0, the opening direction is upward, a ≠ 0

Simple calculation of 4321 * 1234-4322 * 12344

4321*1234-4322*12344
=4321*1234-(4321+1)*12344
=4321*1234-4321*12344-12344
=4321*(1234-12344)-12344
=4321*(-11110)-1234
=-(4321*10000+4321*1000+4321*100+4321*10)-12344
=-48006310-12344
=-48018654