Solving equation 3 / 5 / x = 26 / 45 / 13 / 25

Solving equation 3 / 5 / x = 26 / 45 / 13 / 25

3 / 5 / x = 26 / 45 / 13 / 25. What a ambiguity. Who knows how you divide it
I have solved the problem for you according to my own understanding
3/5：x=26/45：13/25
3/5×13/25= 26x/45
26x/45=39/125
x=27/50

Solution equation (1 + 25%) x = 5 / 8

（1+25%）x=5/8
1.75x=5/8
x=5/8÷1.75
x=5/14

The solution proportion is 4: x = 3:0.25, the solution equation is 5 / 2x-1 / 2 * 3 = 13 / 2

4: X = 3:0.254 / x = 3 / 0.25 (the solution ratio can refer to 1:3 = 5:15 = = > 1 / 3 = 5 / 15) x = 1 / 3 (5x / 2) - (3 / 2) = 13 / 2, 5x-3 = 13 (both sides multiply by 2, the result does not change) x = 16 / 5

In astronomy, "light year" is often used as the distance unit. One light year represents the distance that light travels in a year. It is known that the propagation speed of light is 8 times 3 times 10
In astronomy, "light year" is often used as the distance unit. 1 light year represents the distance of light propagation in a year. Given that the propagation speed of light is 3 × 10 ^ 8 m / s, how many kilometers is 1 light year equal to? (a year is counted as 365 days, and the result retains three significant numbers)
That ah, everyone, because the answer of falling snow is better and more detailed, I adopted his answer.
Don't be angry.

3*10^8=300000000
300000000 * 60 * 60 * 24 * 365 = 94608000000000
94608000000000 / 1000 = 9460800000000 [8 zeros after 8]
∵ keep 3 significant numbers in the result
The scientific counting method is: 9.46 * 10 ^ 12
A: one light year equals 946000000000 km or 9.46 * 10 ^ 12 km
If you think my answer is OK, please accept it in time

Xiaohong, with a mass of 35kg, sits on a sleigh with a mass of 5kg on the horizontal snow. Xiaoli pulls the sleigh with a pull force of 37 degrees to the horizontal direction. The pull force is f = 100N. The dynamic friction coefficient between the sleigh and the ground is u = 0.2 (sin37 = 0.6, cos37 = 0.8, g = 10m / S2)
(1) The pressure of the sled on the ground
(2) The acceleration of sled movement
(3) Time required to advance 150m from standstill

The sled is subjected to four forces: vertical downward gravity (M + m) g, oblique upward tensile force F of 37 degrees, horizontal backward friction UN, and vertical upward supporting force n
(1) In the vertical direction, the acceleration of the sled is zero, so fsin37 + n = Mg + Mg
The results show that n = Mg + mg-fsin37 = 400n-100 * 0.6N = 340n
(2) Suppose that the acceleration of sled motion is a, then it can be obtained from Newton's second law
Fcos37-uN=(M+m)a.
The results show that a = (80n-0.2 * 340n) / (35kg + 5kg) = 0.3n/kg
(3) It takes time t = (2S / a) ^ (1 / 2) = 10 * (10) ^ (1 / 2) (s) [ten times root sign ten seconds] to advance from standstill s = 150m
Notice upstairs, it's on level snow

If the length and width of a rectangle are increased by 12 cm, its area will be increased by 384 square cm. The perimeter of the original rectangle is______ Cm

Let the original rectangle be a cm in length and B cm in width, 12a + 12b + 12 × 12 = 384, & nbsp; 12 (a + b) + 144 = 384, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 12 (a + b) = 240, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; a + B = 20, 20 × 2

Calculate the following formula: 2004 + 6-8 + 10 + 12-14 + 16 + 18-20 + 22 + 24-26 + 28 + +96-98+100．

2004+6-8+10+12-14+16+18-20+22+24-26+28+… +96-98+100=2004+（6-8+10）+（12-14+16）+（18-20+22）+（24-26+28）+… +（96-98+100）=2004+8+14+20+26+… +98=2004+（8+98）×16÷2=2004+106×16÷2=2004+848=2852．...

Given the function f (x) = - x ^ 2-2ax + 1, find the maximum value g (a) of F (x) on [1,3], and find the range of G (a)

Axis of symmetry x = - A
(1) When a

As shown in the picture, a rectangular grassland is 16 meters long and 10 meters wide. There are two paths in the middle. One is a rectangle and the other is a parallelogram. The area of the grassland is______ Square meters

(16-2) × (10-2) = 14 × 8 = 112 (square meters); answer: the area of grassland is 112 square meters

The title is like this: fill in 2.1, 2.5, 2.9, 18.4, 19.2, 18.8, 34.7, 35.1, 35.5 in the box, so that each row, each column, each
The title is like this: fill 2.1, 2.5, 2.9, 18.4, 19.2, 18.8, 34.7, 35.1, 35.5 in the square so that the sum of the three numbers on each row, column and diagonal line is equal! Note: it's a square. Draw nine squares in it. What I want is the calculation steps

2.1 + 2.5 + 2.9 + 18.4 + 19.2 + 18.8 + 34.7 + 35.1 + 35.5) / 3 = 56.4, that is, the sum of the three numbers on each row, column and diagonal is 56.4