Solution equation: 40% + 16 = 80 3x + 10% = 9.3

Solution equation: 40% + 16 = 80 3x + 10% = 9.3

Is that right
40%x+16=80
0.4x=80-16
0.4x=64
x=64/0.4
x=160
3x+10％=9.3
3x=9.3-0.1
3x=9.2
x=9.2/3
x≈3.07

First grade English composition, the best 50 words
I have no idea in English composition,

Percy Buttons I have just moved to a house in Bridge Street.Yesterday a beggar knockd at my door.He asked me for a meal and a glass of beer,In return for this,the beggar stood on his head and sang son...

The ratio of 1 / 2:4 / 5 to the simplest integer is (), and its ratio ()

The ratio of 1 / 2:5 / 4 is (5:8), and its ratio is (5 / 8)

24-x = 13 to solve the equation

24-x=13
-x=13-24
x=11

It is known that the surface area of a cuboid is 184 square centimeters, the bottom area is 20 square centimeters, and the perimeter of the bottom surface is 18 centimeters. What is its volume?

Side area: 184-20 * 2 = 144
Height: 144 △ 18 = 8
Volume: 20 * 8 = 160 CC
This is the first answer. I wish you progress!

A is the second quadrant angle, Tana = - 5 / 4, find cosa, Sina

tana=-5/4,
4sina=-5cosa
sin²a+cos²a=1
Solution
sina=5/√41,cosa=-4/√41

Given that the equation K (x2-2x + 1) - 2x2 + x = 0 has real roots, the value range of K is obtained
Is there a real number root to discuss the format according to the situation

k(x²-2x+1)-2x²+x=0
（k-2）x²+(1-2k)x+k=0
1) When the equation is linear
K-2 = 0 and 1-2k ≠ 0
The solution is k = 2
For generations, x = 2 / 3
2) When the equation is quadratic
If you want it to have roots, you have to
△=（1-2k）² -4（k-2）k
=1-4k+4k² -4k²+8k
=1+4k≥0
Then K ≥ - 1 / 4
k-2≠0
-1 / 4 ≥ k > 2 or k > 2
The range of K is k ≥ - 1 / 4
The format is to write the equation as the standard equation AX & # 178; + BX + C = 0
Then when it is a linear equation, a = 0 and B ≠ 0
Then, when it is a quadratic equation, a ≠ 0 and △≥ 0
The range of K is obtained

Let f (x) be an odd function on R. if x is greater than 0, f (x) = x ^ 2, the inequality f (x + T) ≥ 2F (x) holds for any x ∈ [T, t + 2]
Then the value range of real number T is_____
To answer in detail!
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If x is greater than 0, f (x) = x ^ 2,
x (√2-1)x≤t
x≤(√2+1)t
∴t+2≤(√2+1)t
∴2≤√2t
∴t≥√2

How to solve the equation x - 1 / 6x = 5 / 7

x-1/6x=5/7
5/6x=5/7
x=5/7÷5/6
x=6/7

1. It is known that the distances from a point P (3,2) on the ellipse to the two focal points are 6.5 and 3.5 respectively, and the standard equation of the ellipse is obtained

The standard equation for the ellipse is: the standard equation for the standard equation for the ellipse is: the standard equation for the ellipse is: the standard equation for the standard equation for the ellipse is: x ^ 2 / A ^ 2 / A ^ 2 / A ^ 2 / A ^ 2 / A ^ 2 / a ^ 2 + A ^ 2 / C + X (a ^ 2 / C + X / C + x) and PF2 PF2 Pf1 ^ 2 + y ^ 2 ^ 2 + 2 ^ 2 ^ 2 + 2 ^ 2 + 2 ^ 2 + 2 ^ 2 ^ 2 + PF2 (a ^ 2 / C = 2 / C + x = e (a ^ 2 / C ^ 2 / C ^ 2 / C + x = e (a ^ 2 / C ^ 2 / C ^ 2 / C ^ 2 / C + x) = 6.5, 6.5 (a ^ 2 / C ^ 2 / C ^ 2 / C ^ 2 / C ^ 2 / C ^ 2 / C ^ 2 / C (a ^ 2 / C ^ 2 / C ^ 2 it's not easy