Aunt Zhang has 14 pieces of RMB 5 yuan and 10 yuan, which is just 100 yuan. How many pieces of RMB 5 yuan and 10 yuan? Use the equation

Aunt Zhang has 14 pieces of RMB 5 yuan and 10 yuan, which is just 100 yuan. How many pieces of RMB 5 yuan and 10 yuan? Use the equation

Let five yuan be x, and ten yuan be y
It can be seen from the title
1.X+Y=14
2.5X+10Y=100
Solve the equation and the answer comes out
X=8 Y=6

There are 14 pieces of RMB 5 yuan and 10 yuan, 100 yuan in total. How many pieces of RMB 5 yuan and 10 yuan?
This is the application problem, please write down the steps, thank you

If the square of root sign (- a) is multiplied by B = a root sign B, then the value ranges of a and B are a. A is greater than or equal to 0, B is greater than or equal to 0, Ba is greater than or equal to 0, B is less than or equal to 0. C.A
If the square of root sign (- a) is multiplied by B = a root sign B, then the value ranges of a and B are a. A is greater than or equal to 0, B is greater than or equal to 0, Ba is greater than or equal to 0, B is less than or equal to 0, C. A is less than or equal to 0, B is greater than or equal to 0, d. A is less than or equal to 0, B is less than or equal to 0

Radical (- a) & # 178; b = | - a | radical B = | - a | - radical B = a | - radical B
|If a | = a, then a ≥ 0
If the number of square root is greater than or equal to 0, then B ≥ 0
A ≥ 0, B ≥ 0, the correct answer should be a

5 cubic meters 40 cubic decimeters = () cubic decimeters
83 pages of special training in mathematics class. OK, I'll offer you more

5 cubic meters 40 cubic decimeters = (5040) cubic decimeters

The passenger car and the freight car run from a and B at the same time. They meet each other in five hours. After meeting, the passenger car goes to B in three hours. It is known that the freight car travels 63 kilometers per hour, and how many kilometers per hour does the passenger car travel?

63 × 5 ／ 3, = 315 ／ 3, = 105 (km), answer: the bus travels 105 km per hour

The bulk density of a material is 2.6g/cm3, and the bulk density is 1500kg / m3

(2.6-1.5) / 2.6 = 42.3%, i.e. the porosity is 42.3%

2 (x + 3) - 5 (2-x) = 3 (x-1) solution X / 3-5 = 5x / 2 solution

2(x+3)-5(2-x)=3(x-1)
2x+6-10+5x=3x-3
4x=1
x=1/4
x/3-5=5x/2
2x/6-15x/6=5
-13x=30
x=-30/13

The side area of a cylinder is 628 square centimeters, and its volume is 942 cubic centimeters. What is its bottom area?

The side area of the cylinder is 2 * π * r * h, the volume of the cylinder is = π * r & # 178; * h we know that the side area of the cylinder is 628 square centimeters, the volume is 942 cubic centimeters, the volume of the cylinder / the side area of the cylinder is = π * r & # 178; * H / (2 * π * r * h) = R / 2 = 942 / 628, the solution is: r = 3  the bottom area of the cylinder = π * r & # 178; * 2 (∵ there are two

It is known that a × 67 = B × 65 = 55 × C, a, B and C are not equal to zero______ The largest______ The smallest

Let a × 67 = B × 65 = 55 × C = 1, a × 67 = 1, a = 76, B × 65  1, B = 56, 55 × C = 1, C = 1, and 76 > 1 > 56, that is, a > C > b, so the largest number is a and the smallest number is B. so the answer is: A, B

1. It is known that the sum of the two right angles of a right triangle is equal to 10cm. What is the maximum area and the length of the hypotenuse?
2. Let a, B and C be the three sides of triangle ABC, and prove that a square + b square + C square 〈 2 * (AB + BC + Ca)

1. Let a and B be two right angle sides. A + B = 10 > = 2 √ (AB) 25 > = AB has a maximum area of 25 / 2A ^ 2 + B ^ 2 = (a + b) ^ 2-2ab = 100-25 = 75. The length of oblique side is 5 √ 32. (a ^ 2 + B ^ 2 + B ^ 2 + C ^ 2 + A ^ 2 + C ^ 2) / 2 > = 1 / 2 * 2 (2Ab + 2BC + 2Ac), so a ^ 2 + B ^ 2 + C ^ 2 > = 2 * (AB + BC + CA) the title is wrong