If f (x) is a continuous function, how can f (x) / [f (x) + F (A-X)] find the definite integral on (0, a)

If f (x) is a continuous function, how can f (x) / [f (x) + F (A-X)] find the definite integral on (0, a)

We are the people of the following ((0) and ((0) (((0) ((0) (((0) ((0) (0) {(f (x) / [f (x + F (A-T) / [f (x) (f (x) + F (A-X) (f (x) (f (x) (f (A-T) / [f (x) (f (x) + F (A-X) (f (A-T) / [f (f (A-T (A-T) (f (A-T (A-T) + F (f (A-T) + F (f (f (T) (f (f (T) + F (f (f (A-X) + [f (f (f (f (f (f (f (f (f (x) (x) (x) (x) (x) (f (x) + (f (f (f (f (f (f (f (f (f (f (f (f (x))))} DX + ∫ (0 → a) {f (A-X) / [

Lim [(x, y) - > (0,0)] [(x ^ 3 + x ^ 5) / (X & # 178; + Y & # 178;) limit is

(x, y) → (0,0) LIM (x ^ 3 + x ^ 5) / (x ^ 2 + y ^ 2) replace x = ρ cos θ, y = ρ sin θ = LIM (ρ→ 0) (ρ ^ 3cos ^ 3 θ + ρ ^ 5cos ^ 5 θ) / ρ ^ 2 (sin ^ 2 θ + cos ^ 2 θ) = LIM (ρ ^ 3cos ^ 3 θ + ρ ^ 5cos ^ 5 θ) / ρ ^ 2 = Lim cos ^ 3 θ + ρ ^ 3cos ^ 5 θ because cos ^

Ask a smart person. ABCD times 4 equals DCBA to find out what ABCD is

1. ABCD multiplied by 4 is equal to DCBA, four digit multiplied by 4 or four digit, the highest bit has no carry, which means that a can only be 1 or 2, and D multiplied by 4 can get a, a can only be 2. At the same time, D of DCBA is a multiplied by 4 on thousand bits, so d must be 8 (if 9, 9 multiplied by 4 will not get a bit 2). B in ABCD can only be 1 or 2 (without carry, it can not be 3 or more numbers)
2. ABCD multiplied by 4 equals DCBA, that is, DCBA can be divisible by 4. According to the characteristics of the number divisible by 4 (the last two digits can be divisible by 4), Ba may be 12, not 22, so B must be 1
3. Substituting a = 2, B = 1, d = 8 into ABCD multiplied by 4 equals DCBA, it is easy to get C = 7
So ABCD is 2178
It's a stupid way for stupid people. It feels OK!

What is the intercept of the function y = - 5x + 2 on the Y-axis and the area of the triangle enclosed by the two axes

You'll know when you draw. Use x = 0 and y = 0 to draw

If a cylinder with a diameter of 2 decimeters at the bottom is cut off and a cylinder with a height of 1 decimeter is cut off, the surface area of the original cylinder will be reduced______ Square decimeter

14 × 2 × 1 = 6.28 (square decimeter). A: the surface area of the original cylinder is reduced by 6.28 square decimeter

-9. - 9, 5, 12 (counting 24 points)
I can't wait a long time

Ah, study hard and use your brain more! The special operations are as follows: √ ((- 9) * (- 9)) - 5) * 12 = 2 * 12 (12-5 - √ ((- 9) * (- 9))))! = 4! The conventional operations are as follows: 1: (- 9) × ((- 9) - 5)) - 122: (- 9) × ((- 9) - 5) - 123: (- 9) - ((- 9) - 12) × 54: (- 9) - (((

Find the tangent equation and normal plane equation of the curve X = asin ^ 2T, y = bsintcost, z = CCOS ^ 2T at the point corresponding to t = n / 4

It's the tangent equation of T = π
x'(t)=2asintcost=asin2t
y'(t)=bcos2t
z'(t)=-2ccostsint=-csin2t
x0=a y0=b/2 z0=0
x'=a y'=0 z'=-c
x-a z
｛ --- =---
a -c
y=b/2
Tangent plane equation
a*(x-a)-cz=0

How to convert feet, inches and meters
For example: is 5'3 "converted into meter 5.3 × 0.3

1 foot = 12 inches
5'3 "= 5 ft 3 in = 5.25 ft = 1.6002m

If the perimeter of the diamond is 20cm and the ratio of two adjacent edges is 1:2, the length of the shorter diagonal is? And the distance between a group of opposite edges is?

The ratio of two adjacent angles is 1:2
The sum of two adjacent angles is 180 degrees
The angle of the shorter diagonal pair is 60 degrees
The shorter diagonal length is equal to the side length 20 △ 4 = 5
The distance between a group of opposite sides is 5 √ 3 / 2

Let a, B, C be real numbers, and a ≠ 0, the parabola y = AX2 + BX + C intersects the X axis at two points a and B, intersects the Y axis at point C, and the vertex of the parabola is on the straight line y = - 1. If △ ABC is a right triangle, then the maximum area of RT △ ABC is ()
A. 1B. 3C. 2D. 3

Let y = AX2 + BX + C intersect Y-axis at point C (0, c), C ≠ 0, intersect X-axis at points a (x1, 0), B (X2, 0), and x1 ＜ 0 ＜ x2. From △ ABC is a right triangle, we know that point C must be a right triangle vertex, and C2 = (- x1) x2 = - x1x2 (inverse theorem of projective theorem)