Which of the following situations are possible? Please explain according to examples. (1) the speed of the object is very large, and the acceleration is very small. (2) the speed of the object is equal to 0, and the acceleration is not equal to 0. (3) the speed of the object is constant, and the acceleration is not equal to 0

Which of the following situations are possible? Please explain according to examples. (1) the speed of the object is very large, and the acceleration is very small. (2) the speed of the object is equal to 0, and the acceleration is not equal to 0. (3) the speed of the object is constant, and the acceleration is not equal to 0

1 exists. The speed of the train is 180km / s, but it brakes when it is far away from the station. The braking acceleration is about 10
When you are running, your friend pulls you, you stop, the speed is 0, but you will be pulled back by him. The acceleration is not equal to 0
3. It doesn't exist

Which of the following situations may exist? Give an example
The speed of an object is very high and the acceleration is very small
The velocity of a body is equal to zero, but the acceleration is not equal to zero
The velocity of the object is constant, the acceleration is not equal to zero
The velocity of the object varies greatly and the acceleration is very small
The speed of an object changes very slowly, but the acceleration is very large
Object speed to the right, acceleration to the left
I just learned acceleration. I'm not very good at it. Be patient,
I'm a freshman in high school, and I haven't learned circular motion yet

As above, 1,6 are correct, but 2,4 are also correct
2. When you hold an object in your hand and release your hand, the object does not move, the speed is 0, and the acceleration is not 0 due to the gravity of the earth
4. Uniform circular motion with constant speed

For example: when the velocity of an object is zero, the acceleration may or may not be zero
ditto

The simplest way is to hold a ball in your hand and let it fall. At the moment of release, the speed is 0, but the acceleration is g. the acceleration of gravity. Because the speed of the ball will increase immediately, because the acceleration
And you don't let go, because your force balances gravity, then the velocity and acceleration are both 0

If x / y = 2 / 3, then x ^ 2-y ^ 2 / x ^ 2-2xy + y ^ 2 divided by XY + y ^ 2 / x ^ 2-xy

Original formula = (x + y) (X-Y) / (X-Y) ^ 2 △ y (x + y) / (x + y) (X-Y)
=(X+Y)/(X-Y)÷Y(X-Y)
=(X+Y)/(X-Y)×(X-Y)/Y
=(X+Y)/Y
=X/Y+Y/Y
=2/3+1
=5/3

A very simple one variable quadratic equation problem!
If two of the quadratic equations 2x ^ 2-7x + M = 0 with respect to X are reciprocal to each other, then M=___

M = 2. According to the relation between and coefficient, let one of the roots be a, then the other root is 1, and the product of the two roots is 1, that is, M = 2, so m is 2

When x is what, the value of fraction X2 - 4x + X2 - 9 is 0?

When x = 3

Solving sales problem with linear equation of one variable
If the price of a commodity is increased by 25%, if the sales volume is not good and the original price is restored, what percentage of the price should be reduced
When I'm just getting started, I always come across such questions: what's the specific process? Who can tell me,

25%/(1+25%)=20%
The original price of the commodity is 1, and it is (1 + 25%) after an increase of 25%
If the original price is reduced to 1, then the reduction is (1 + 25%) - 1 = 25%
Difference of price reduction / increased price * 100% = percentage of price reduction

What is the coefficient of the term with unknowns

3 / 7 π, - 1

5x-7 = 4x, how to solve this equation?

I'll give you the process directly!
: 5x = 4x + 7 (move to change sign)
5x-4x=7
X = 7 (coefficient reduced to 1)

We know that the quadratic power of | a-c-2 | + (3a-6b-7) + | 3B + 3c-4 | = 0

The solution of a-c-2 = 0 3a-6b-7 = 0 3B + 3c-4 = 0 is a = 2 and 11 / 15, B = 3 / 5, C = 11 / 15