Is it possible for an object to speed to the right and accelerate to the left? Please give an example to illustrate ~ ~ urgent! Wait online ~ ~ thank you Questions on page 26 of high school physics exercise book~~~

Is it possible for an object to speed to the right and accelerate to the left? Please give an example to illustrate ~ ~ urgent! Wait online ~ ~ thank you Questions on page 26 of high school physics exercise book~~~


Of course, there are many examples. Car braking is the most common example. Acceleration has direction and speed also has direction. In addition, you block and push the oncoming cart in the opposite direction. The speed of the car is towards you, but it's deceleration. At this time, you give the car a force opposite to the speed, so



As shown in the figure, when the car accelerates to the right, the block m is stationary on the vertical wall of the car relative to the car. When the car's acceleration increases ()
A. M's static friction increases, B. M's pressure on the car wall increases, C. m may fall onto the car, D. M's static friction remains unchanged


A. according to Newton's second law, the friction force F = mg remains unchanged. So a is wrong and D is correct. When the acceleration of B and C cars increases, the elastic force n = ma increases, and the maximum static friction force on the block increases. The block cannot slide along the wall. So B is correct and C is wrong. So BD is selected



When the car starts from a standstill, that is, the acceleration a is uniformly accelerated, then the speed of the car ()
A. At the same time, the maximum value B. has not reached the maximum value C. has reached the maximum value d before reaching the rated power. After that, the speed will remain unchanged


When the car just reaches the rated power, it also has acceleration, from f-f = ma and P = FV, then f gradually decreases, acceleration a also gradually decreases, and the speed continues to increase, until the acceleration is zero, the speed reaches the maximum, so ACD is wrong, B is correct. So select B



x^2-9y^2-x-3y
With the help of those who have done wrong


x^2-9y^2-x-3y=(x+3y)(x-3y)-(x+3y)=(x+3y)(x-3y-1)



The square of (x + 2) - 5x + 6 = 12
Using formula method


The square of (x + 2) - 5x + 6 = 12
x² +4x+4 -5x +6 -12 = 0
x² -x -2 = 0
(x-2) (x+1) = 0
X = 2 or - 1
In terms of formula
quadratic formula
X = 1 ± root (1 + 8) / 2
=( 1 ±3) / 2
=2 or - 1



Given the square of a + B-2 + (AB + 3) = 0, find the value of 2 [AB + (- 3a)] - 3 (2B AB)
Requirements: ensure the correctness, accuracy and integrity of the process


If one is greater than 0, the other is less than 0
So both are equal to zero
So a + B-2 = 0, AB + 3 = 0
a+b=2,ab=-3
Original formula = 2ab-6a-6b + 3AB
=5ab-6(a+b)
=5×(-3)-6×2
=-15-12
=-27



5x-39 = 56 solution test


5x-39=56
5x-39+39=56+39
5x=95
5x÷5=95÷5
x=19



24x+180-32x=102


24x+180-32x=102
180-102=32x-24x
8x=78
x=39/4



Solve the following equation (1) 2 / 7 times (X-7) = 2 minus 2x / 3


3



How to turn off the scientific calculator for students


There are two ways. If there is an ellipse in the middle, press shift first, then AC, and if there is no ellipse, press off directly