If the equation (the absolute value of K-2) x ^ 3 + kx-k ^ 2 / 2 = 0 about X is a linear equation of one variable, then k =? X =?

If the equation (the absolute value of K-2) x ^ 3 + kx-k ^ 2 / 2 = 0 about X is a linear equation of one variable, then k =? X =?

Given that the expansion of (x ^ 2 + MX + n) (x ^ 2-3x + 2) does not contain x ^ 3 and X terms, find the value of M and n

(X^2+mx+n)(x^2-3x+2)
=x^4+(m-3)x³+(2+n-3m)x²+(2m-3n)x+2n
∵ does not contain x ^ 3 and X items
∴m-3=0
2m-3n=0
∴m=3
n=2

Given that (m ^ 2 + MX + 3) (x ^ 2-3x + n) expansion does not contain x ^ 2 and x ^ 3 terms, find the value of M.N

(mx²+mx+3)(x²-3x+n)
Take it out and sort it out
=mx^4+(m-3m)x³+(n-3m+3)x²+(mn-9)x+3n
Without X & sup2; and X & sup3;, their coefficients are 0
So m-3m = 0
n-3m+3=0
m=0
n=3m-3=-3

Twelve and thirteen eight minus two and twenty-two nine minus five and twenty-two seven

12 8 / 13-2 9 / 22-5 7 / 22
=12 8 / 13 - (2 9 / 22 + 5 7 / 22)
=12 and 8 / 13-7 and 8 / 11
=4 and 127 / 143

The distance between the two places is 120 kilometers. A and B cars leave from the two places at the same time. They travel in opposite directions for 2 / 3 hours and meet each other. The speed ratio of a and B is 4:5. How many kilometers does a and B travel per hour
Formula

A: 80 km / h
B: 100 kilometers per hour
120 divided by 2 / 3 equals 180 (km)
180 divided by (4 + 5) multiplied by 4 equals 80 (km)
180 minus 80 equals 100 (km)

The decimal point of a decimal is moved two places to the left, which is 11.88 less than the original number. The original number is ()

Original number = 11.88 (1-0.01) = 12

A and B cars go from A. B, which is 340km away from each other, and a car leaves at 8 am

Meeting time = total distance divided by speed and T = (340-0.5 × 30) / (30 + 35) = 5 hours, meeting time is 1:30 p.m. (8:30 + 5 hours)

It is known that the opposite sides of the inner angles a, B and C in the acute angle △ ABC are a, B and C respectively, a & # 178; + B & # 178; = 6abcosc, and Sin & # 178; C = 2sinasinb
(1) Find the value of angle C;
(2) Let f (x) = sin (ω X - π / 6) - cos ω x (ω > 0), and the distance between two adjacent highest points on the image of F (x) be π, then the value range of F (a) can be obtained

At the acute angle of △ ABC, in the case of sin # 178; C = 2sinasinb, we can get C # 178; C = 2sinasinb, and we can get C \35; 178; = 2Ab because a \\\\35\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\(?) 178; 2 (A &?) 178; + B &...)

If train a is 225 meters long, 25 meters per second, and train B is 20 meters per second, the time of passing by is 9 seconds? (2) How many seconds does it take for train a to pass through this platform? (3) How many seconds did it take Xiao Ming on train a to see train B pass?

(1) (20 + 25) × 9-225 = 180 (m); (2) 225 ／ 25 = 9 (s); (3) 180 ／ (25 + 20) = 4 (s); a: train B is 180 meters long, and it takes more than 9 seconds for train a to pass this platform, while Xiaoming on train a takes 4 seconds to see train B pass

There are four groups in a class. The number of students is arranged as follows: 10, 10, x, 8. If the median of this group of data is equal to the average, then x is equal to?
What's x?

x=9