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Solving mathematical problems (requires a system of linear equations with three variables) A correspondent rides a bicycle to send a message to the mountain post. The speed from the camp to the foot of the mountain is 15 km / h, the speed up the mountain is 10 km / h, and he returns immediately. The speed down the mountain is 30 km / h. if it takes 2.4 hours to go back and forth, how much is the total distance
A correspondent rides a bicycle to send a message to the mountain post. The speed from the camp to the foot of the mountain is 15 km / h, the speed up the mountain is 10 km / h, and he returns immediately. The speed down the mountain is 30 km / h. if it takes 2.4 hours to go back and forth, how much is the total distance
Let the horizontal road be x and the mountain road be y
2X/15+Y/10+Y/30=2.4
Let's split it
4X/30+4Y/30=2.4
4（X+Y）/30=2.4
4（X+Y）=72
The total round trip distance is 2 (x + y) = 36 km
A: the round trip is 36 kilometers in total
If the polynomial 1 / 2x ^ (m-1) - (n-3) x + 2 about X is a cubic binomial, then 3m-2n=
According to the meaning of the title
m-1=3
n-3=0
∴m=4
n=3
∴3m-2n
=12-6
=6
Finding the number of real roots of equation │ X-2 │ + │ x-3 │ = 1
The sum of the distances between X and 2,3 points
Because the distance between two and three is one
So when x is between 2 and 3
The sum of distances is 1
So there are countless solutions
Fifth grade disjunctive problem
emergency
75÷〔138÷（100-54）〕 85×(95－1440÷24)80400－(4300＋870÷15) 240×78÷（154-115）1437×27＋27×563 〔75-（12+18）〕÷152160÷〔（83-79）×18〕 280＋840÷24×5325÷13×(266－250) 85×(95－1440÷24)...
If y = an equation of X, is the geometric meaning of Y 'obtained by derivation the tangent slope k, and the derivative function y' = an equation of X is the relationship between K and X?
In this geometric application, it's a relation you said
For example, the derivative of a quadratic function (parabola) is a straight line. When the interval of linear equation > 0, the parabola is an increasing function;
Given a = m + 6, B = m + 4, C = m + 3, find the square of a + the square of B + the square of C - AB BC ca
a^2+b^2+c^2-ab-bc-ca
=[(a-b)^2+(b-c)^2+(c-a)^2]/2
=(2^2+1^2+3^2)/2
=7.
I want to know the CPK calculation formula and the principle of the calculation formula? I hope to give an answer
Why CPK ≥ 2.0 is excellent; 2.0 > CPK ≥ 1.67 is excellent; 1.67 > CPK ≥ 1.33 is good; 1.33 > CPK ≥ 1.0 is general; 1.0 > CPK ≥ 0.67 is poor; 0.67 > CPK is not acceptable? Who made it? What is the judgment benchmark? Why do you make such a judgment
The formula is CPK = (usl-x mean) / 3sigma or (x mean LSL) / 3sigma, take the smaller value. If CPK = 2, according to the above formula, the nearest distance between the mean and both sides is 6 times of sigma, that is, 6 sigma level. According to the normal probability calculation, most of the points fall within the tolerance line, only
3x^2-2x+5-6x^2+3x-9
The teacher asked us to do this problem before we learned it, but I had to do it. I had to go online to find the answer
Original formula = (3-6) x ^ 2 + (3-2) x + 5-9
=-3x^2+x-4
The side length of a rectangle is 88cm. If the width increases by 25%, the length decreases by 1 / 7, and the perimeter remains unchanged, calculate the area of the rectangle
88/2=44(cm)
If the length is x cm, the width is 44-x cm
x*(1-1/7)+(44-x)*(1+25%)=44
x=28
Width: 44-28 = 16 (CM)
The length is 28 cm and the width is 16 cm
A 168 cm long iron wire is welded into a rectangular model with the ratio of length, width and height of 3:2:1. How many cm are the length, width and height of the model?
3 + 2 + 1 = 6168 △ 4 = 42 (CM), 42 × 36 = 21 (CM), 42 × 26 = 14 (CM), 42-21-14 = 7 (CM). A: the length, width and height of this model are 21 cm, 14 cm and 7 cm respectively
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