Solving practical problems with linear equation of one variable A batch of saplings will be collected by each class according to the following methods: the first class will receive 100 saplings and the remaining 1 / 10 saplings, the second class will receive 200 saplings and the remaining 1 / 10 saplings, and the third class will receive 300 saplings and the remaining 1 / 10 saplings Finally, all the saplings are collected, and the saplings of each class are equal

Solving practical problems with linear equation of one variable A batch of saplings will be collected by each class according to the following methods: the first class will receive 100 saplings and the remaining 1 / 10 saplings, the second class will receive 200 saplings and the remaining 1 / 10 saplings, and the third class will receive 300 saplings and the remaining 1 / 10 saplings Finally, all the saplings are collected, and the saplings of each class are equal


Set X saplings
100+1/10(X-100)=200+1/10【X-200-100-1/10(X-100)】
The solution is x = 8100
8100 / [100 + 1 / 10 (8100-100)] = 9 (pieces)
A: there are 8100 trees and 9 classes
Our teacher has said, guarantee right!



The application problem of solving one variable equation of one degree!
A and B wait for a mountain. A climbs 10 meters per minute and starts 30 meters early. B climbs 15 meters per minute and both of them climb to the top of the mountain at the same time. How long does a spend climbing? How high is the mountain?


Suppose B takes X minutes to climb the mountain
10*30+10x=15x
The solution is x = 60
Time: 60 + 30 = 90 (minutes)
Mountain height: 60 * 15 = 900m



On a plan with a scale of 1:5000, the actual distance represented by a line segment of 6cm is______ Rice


6 ÷ 15000 = 30000 (CM), 30000 cm = 300 m; answer: the actual distance indicated by 6 cm line segment is 300 m; so the answer is: 300



The hour hand rotates () degrees from 8:45 to 9:9
The sum of 1 + 3 + 5 + 7 +. + 205 is a () number
Don't be direct, formula!


360/(6*12)=6 6*(15+9)=144
(205-1) / 2 + 1 = 103 the sum of 103 odd numbers is odd



How to calculate gram weight with small cloth


Less than 10 cm circle
If it is irregular, cut it into a regular shape and calculate its area;
Suppose: 4cm * 4cm = 16 square centimeter, the cloth weight is 0.12g
Square meter (GSM): 10000 divided by 16 = 625 * 0.12 = 75g
I'm just a used cloth collector



Calculate the area of the shadow in the figure below. (unit: cm)


The sum of the areas of two squares - the area of a triangle
10×10+5×5-10×(10+5)÷2
=100+25-75
=50



What are the axisymmetric figures
How many axes of symmetry are there


There is one line in the line
There is one corner;
There is one isosceles triangle;
There are three equilateral triangles;
There are two rectangles;
There are four squares;
An isosceles trapezoid has one
There are two diamond shapes
The semicircle has one
There are countless lines in the whole circle
There are five five five pointed stars
There are six regular hexagons
There are seven regular heptagraphs
wait



Given that x, y, Z are positive integers, and x < y, when x + y = 2007, Z-Y = 2008, find the sum of the largest and the least of all the values of X + y + Z?


X + y + Zmax = 2007 + Zmax
When Z is the maximum, y is the maximum
Y = 2007-x = 2006
Z=2008+2006=4014
So x + y + Z = 2007 + 4014 = 6021



Given that the vector AB is a non-zero vector and a + B = A-B, we prove that a is perpendicular to B


If the two sides are squared at the same time, the vector a * vector b = 0 is obtained



Triangle ABC, ACB = 90 ° angle bisector of triangle intersection of foot point O 3, OD vertical BC, AB vertical, D point, e, f pedal, BC = 8 cm, CA = 6 cm, what is the distance from o point to three sides AB, AC and BC


Bisector of passing angle, OE
=Author = od angle = 90 degrees, so odce is a square set OE = x, so OE = of =? Od = CE = CD = XAE = 8-x=
Affb = 10 - (8-x know) = 2 + x = BD BC = 6 = BD + DC = 2 + X + x 2, x = 6=
2