The four literary genres mainly refer to novels, poems, proses and ()

The four literary genres mainly refer to novels, poems, proses and ()


The four literary genres refer to poetry, novel, prose and drama



The story names of "three" in four famous works "a dream of Red Mansions", "journey to the west", "outlaws of the marsh" and "Romance of the Three Kingdoms"
All of them!


Dream of Red Mansions: Golden mandarin duck three xuanya card order journey to the West



Point a is the midpoint on one side of the rectangle. If the area of the rectangle is 40 square centimeters, the area of the trapezoid is () square centimeters, and the area of the triangle is?
I must help, please brothers and sisters~


Trapezoid area is three fourths of the total area, that is 30
The area of a triangle is one fourth of the total area, that is, 10
Draw a picture for yourself



The interval of solution of equation lgx = 3-x is ()
A. (0,1)B. (1,2)C. (2,3)D. (3,4)


When x = 2, lgx = LG2, 3-x = 1. ∵ LG2 ﹤ 1 = LG10, ∵ x0 ﹥ 2, then judge x0 ∈ (2, 3), the answer is (2, 3)



Xiaodong took a long bamboo pole into a 3-meter-wide gate. He couldn't take it horizontally, but he took it vertically. As a result, the pole was one meter higher than the gate
Xiao Dong took a long bamboo pole into a 3-meter-wide gate. He couldn't take it horizontally, but he took it vertically. As a result, the pole was one meter higher than the gate. When he tilted the pole, its two ends were just against the opposite corner of the gate. He asked how long the pole was?


Let the length of rod be X
The Pythagorean law is: x ^ 2 = 3 ^ 2 + (x-1) ^ 2
x^2 = 9 + x^2 - 2x + 1
2x = 10
x = 5
So the length of the pole is 5m



If (2x + 3) (4-5x) = ax ^ 2 + BX + C, then a = (), B = () C = ()


(2x+3)(4-5x)=8x-10x^2+12-15x=-10x^2-7x+12
So a = - 10, B = - 7, C = 12



The area of a triangle is 2.5 square centimeters. What is the area of a parallelogram with the same base and height


Let the base of a triangle be x and the height be y, then its area is (1 / 2) xy = 2.5 square centimeter. Because the parallelogram has the same base and height as the triangle, its area is xy = 5 square centimeter



Log (a) (b) = log (b) (a) (a ≠ 1, B ≠ 1, C ≠ 1), then ab=
(log (x) (y)) ^ 2 + (log (y) (x)) ^ 2 = 1, then y can be expressed as
The preceding bracket is the base


Is it a ≠ 1, B ≠ 1, a ≠ B?
= = = = = = = = =
1. Let t = log (a) (b),
Then log (b) (a) = 1 / T
So t = 1 / T,
The solution is T1 = 1, T2 = - 1
And because a ≠ B,
So log (a) (b) ≠ 1
So log (a) (b) = - 1,
That is, B = a ^ (- 1) = 1 / A
That is ab = 1
= = = = = = = = =
2. Let t = log (x) (y), x, y belong to (0,1) U (1, positive infinity)
Then log (y) (x) = 1 / T
That is T ^ 2 + 1 / (T ^ 2) = 1
That is T ^ 4-T ^ 2 + 1 = 0
The equation has no real root
.
= = = = = = = = =
Maybe it's wrong. Check the question again



After the formula of equation x2-3x + P = 0, we get (x + m) 2 = 12. (1) find the value of constant P and m; (2) find the root of the equation


(1) ∵ x2-3x + P = 0, ∵ x2-3x = - P, x2-3x + (32) 2 = - P + (32) 2, (x-32) 2 = - P + 94, ∵ M = - 32, - P + 94 = 12, the solution is: P = 74, M = - 32; (2) ∵ x2-3x + P = 0, ∵ x-32) 2 = 12, x-32 = ± 22, that is, the solution of the equation is: X1 = 3 + 22, X2 = 3 − 22



Given the circle C: (x-1) ^ 2 + (Y-2) ^ 2 = 2, the coordinates of point P are (2, - 1), the tangent of circle C is set through point P, and the tangent point is a, B.1, the equation for finding the straight line PA, Pb is obtained
2 find the length of the tangent of the circle passing through point P 3 find the equation of the straight line ab


The tangent line of a circle passing through point P is y + 1 = K (X-2) -- > kx-y-2k-1 = 0, and its distance from the center of the circle (1,2) is equal to the radius "root 2", so | k-2-2k-1 | / root (1 + K ^ 2) = root 2 --- > k ^ 2-6k-7 = 0, k = 7, or K = - 1