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Write two different English diaries. Record the situation of helping the group's mother do housework at home on Sunday
November,6th,Sunday,sunny
Today is Sunday.Dad went to work early in the morning.
At about seven,I got up.Mom cooked breakfast for us.It was yummy.After breakfast,I helped mom do some housework.First I washed the dishes.I washed them very carefully.And mom praised me.Then I washed some of my clothes.Mom washed all of the rest.I couldn't wash so fast as my mom,but I tried my best.After that, I cleaned the window with mom.Every time I finished one,I had a look at it,and found it was bright and clean.I was very happy.
Finally,in the afternoon,I swept the floor and mopped it.When Dad came back home,He was surprised and said I was a very good boy.I was happy.
November,6th,Sunday,sunny
It is Sunday today,and it was sunny.But Mom told me I couldn't go out.Because it was cold and she holped me keep away from catching a cold.It was boring and I was unhappy.After breakfast,Mom told me to help her with the housework.It was better than having nothing to do.First I helped mom clean the window.It was uneasy to make them very clean,but I tried my best.Then I washed my clothes.Mom taught me how to make them clean.I washed them with a soap.And then,I mopped the floor,I did a good job,and mom praised me for that.Finally ,in the evening,I helped my mom cook rice.Mom said it was delicious.
English composition about doing housework
About doing housework, mainly means that family members like to do housework, do not like to do housework
Within an hour
On weekends,I often help mum do some washing,I can't cook .But my sister often does some cooking,because she likes it .My brother often clean our rooms,sometimes he help my father wash our car.My fath...
Help parents do housework
The contents should include:
1. Do you think it necessary to help your parents with the housework?
2. Tell me about your experience in helping your parents with housework
3. What do you learn from doing housework? About 80 words
Do the housework.A day ,I sit there is no thing on the sofa and do it ,And but mama in busy inside the housework is doing in busy other parts of country.Saw mama 's busy figure ,― of an idea flashes ...
When x is 2, (x-x & # 178; - 5) - (2x & # 178; + 7x-3) is equal to []
The first solution is - 6x-3x & # 178; - 2 = - 26
Under what conditions do the following three questions hold? The square of a is greater than a, the absolute value of a is greater than a
a²＞a
a²-a＞0
a（a-1）＞0
A > 1 or a < 0
a＞-a
2a＞0
a＞0
The absolute value of a is greater than a
a＜0
Calculate 4x quartic y quadratic - 5x quadratic y quadratic - 9y quadratic
4X quartic y quadratic - 5x quadratic y quadratic - 9y quadratic
=y^2(4x^4-5x^2-9)
=y^2(x^2+1)(4x^2-9)
=y^2(x^2+1)(2x+3)(2x-3)
What is the integral of solving the x power of E and the negative 1 / 2 power of X?
Your title is wrong, it should be 1 / 2x power of E, and then it should be done with the substitution method
Let two nonzero vectors E1 and E2 not be collinear, if AB = E1 + E2, BC = 2E1 + 8e2, CD = 3 (E1-E2), if module E1 = 2, module E2 = 3, and the angle between E1 and E2 is 60 degrees, then K is determined to make Ke1 + E2 perpendicular to E1 + Ke2
Because Ke1 + Ke2 is perpendicular to E1 + Ke2, the product between them is zero, that is, (Ke1 + Ke2) (E1 + Ke2) = 0, and then the expansion is because E1 * E1 = 4, E1 * E2 = 2 * 3 * cos60 = 3, E2 * E2 = 3 * 3 * cos0 = 9. By substituting into the above expansion, we can get an equation about K. by solving it, we can get the value of K. as for AB, BC, CD are
3x-5y+2z=1 4x+5y-z=5 x-5y+3z=-2
3x-5y+2z=1 (1)
4x+5y-z=5 (2)
x-5y+3z=-2 (3)
(1) (2) 7x + Z = 6 (4)
(2) + 3 gives 5x + 2Z = 3 (5)
(4) X2 - (5) is 9x = 9, so x = 1
Substituting x = 1 into (4) yields z = - 1
Substituting x = 1 and z = - 1 into (1) yields y = 0
The results are: x = 1, y = 0, z = - 1
Solution equation: 0.5x = 0.01 + 3 / (5x)
And 0.4x = 0.8 (1 / 30 + 1 / x) thank you
1. Multiply both sides by 5x:
2.5x^2-0.05x=3
50x^2-x-60=0
x1=[1+√(1+12000)]/100=0.01+√1.2001
x2=0.01-√1.2001
2. x=2(1/30 + 1/x)
15x^2-x-15=0
x1=[1+√(1+900)]/30=(1+√901)/30
x2=(1-√901)/30
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