Xiao Ming bought three kinds of stationery: pencil, eraser and exercise book. It is known that their numbers are different prime numbers and satisfy the equation: number of pencils * (number of pencils + eraser)

Xiao Ming bought three kinds of stationery: pencil, eraser and exercise book. It is known that their numbers are different prime numbers and satisfy the equation: number of pencils * (number of pencils + eraser)


Xiao Ming bought three kinds of stationery: pencil, eraser and book. It is known that their numbers are different prime numbers, and satisfy the pencil number x (eraser number + book number) = 110 + book number. Question: Xiao Ming bought () erasers. It is not difficult to solve this problem, but the difficult point is the entry point. This problem provides two important conditions: first



Xiao Hong bought 5 ballpoint pens and 3 pencils at the stationery store, which cost 2.90 yuan. It is known that each pencil costs 0.30 yuan. How much is each ballpoint pen?


(2.90-0.30 × 3) △ 5, = (2.90-0.90) △ 5, = 2 △ 5, = 0.4 (yuan); answer: each ballpoint pen is 0.4 yuan



Xiao Ming went to a stationery store to buy pencils and erasers for 30 students in the school art activity group
Xiao Ming went to a stationery store run by wholesale and retail businesses to buy pencils and erasers for 30 students in the art activity group of the school. According to the rules of the store, if you buy 2 pencils and 1 eraser for each of the group, you must pay 39 yuan at the retail price; if you buy 3 lead pens and 2 erasers for each of the group, you can pay 39 yuan at the wholesale price, It is known that the wholesale price of each pencil is 0.1 yuan lower than the retail price, and the wholesale price of each rubber is 0.25 yuan lower than the retail price. How much is the wholesale price of each pencil and rubber in this shop?


If the wholesale price of pencil is X Yuan and the wholesale price of rubber is y yuan, then the retail price of pencil is x + 0.1 yuan and the retail price of rubber is y + 0.25 yuan
30*(2(x+0.1)+y+0.25)=39
30*( 3x+2y)=42
The solution of the equations is x = 0.3, y = 0.25
A: the wholesale price of each pencil and rubber in this shop is 0.3 yuan and 0.25 yuan respectively



(5*11x-10)/(11x)=(5×7x+10)/(7x+4)
(5*11x-10)/(11x)=(5×7x+10)/(7x+4)


Extract the common factor to get [5 (11x - 2)] / (11x) = [5 (7x + 2)] / (7x + 4)
Divide both sides by 5 to get (11x - 2) / (11x) = (7x + 2) / (7x + 4)
Remove the denominator to get (11x - 2) (7x + 4) = (7x + 2) (11x)
Remove brackets to get 77X & # 178; + 44x - 14x - 8 = 77X & # 178; + 22x
It is reduced to x = 1



Simple calculation by factorization 2 * 101 ^ 2-2 * 101 * 102 + 2 * 51 ^ 2


A:
2*101^2-2*101*102+2*51^2
=2*(101^2-101*102+51^2)
=2*(101^2-2*101*51+51^2)
=2*(101-51)^2
=2*50^2
=2*2500
=5000



In the triangle ABC, the points D and E are on the edge BC, the angle BAE = angle CAD, the angle ade = angle AED


Syndrome: according to the sum of the internal angles of triangles is 180 degrees, the following results are obtained
Angle CAD + angle ade + angle c = 180 degree
Angle BAE + angle AED + angle B = 180 degree
Because: angle CAD = angle BAE
Angle ade = angle AED
So: angle B = angle C



How many centimeters are one foot, one inch and one foot?


In Han Dynasty, one foot equals 23.1 cm, in Wei and Jin Dynasties, 26.7 cm in Sui and Tang Dynasties, and 30.72 cm in song and Yuan Dynasties
Ten feet is one foot
Ten inches make a foot
It is generally believed that:
One foot = 333.333cm
One foot = 33.3333 cm
1 inch = 3.333 cm



A rectangular playground is 60 meters long and 30 meters wide. Draw its plan with a scale of 1:1000


Hello, Hanying. Warm for you
On the picture
60m = 6000cm
30 m = 3000 cm
Length: 6000 × 1 / 1000 = 6cm
Width: 3000 × 1 / 1000 = 3cm
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How to prove that the sum of squares of the lengths of three middle lines of a triangle is equal to 3 / 4 of the sum of squares of the lengths of three sides





1. The square of a - the square of X + 2x-1 = the square of a - ()
2. Square of X - (square of Y - x + y) = square of X - square of Y + ()
3.(2a-b+c)(2a+b-c)=【2a-( )】【2a+( )】


1. The square of a - the square of X + 2x-1 = the square of a - (X & # 178; - 2x + 1)
2. Square of X - (square of Y - x + y) = square of X - square of Y + (X-Y)
3.(2a-b+c)(2a+b-c)=【2a-( b-c )】【2a+( b-c )】