I bought a pen, notebook, stationery and schoolbag in the mall

I bought a pen, notebook, stationery and schoolbag in the mall


Stationery includes pen and schoolbag, so I bought pen, notebook and schoolbag in the mall



We need 35 pens with a unit price of 2 yuan. Wenhai pen shop: buy 6 pens and get one free. Stationery store: all goods are 10% off
Department store: 50 yuan, 20% discount. Which one is the best?


Wenhai Bizhuang: buy 6 free one, a total of 35, so buy 30 free 5, need 2 * 30 = 60 yuan
Stationery store: 10% off, 2 * 35 * 0.9 = 63 yuan
Department store: I'm not sure what it means. 2 * 35 * 0.8 = 56 yuan if it's 50% off, 50 * 0.8 + (2 * 35-50) = 60 yuan if it's 50% off



The stationery counter in the shopping mall bought a batch of "hero" brand pens at the price of a (a as an integer) yuan, and decided to increase the price by 2 yuan for each pen. Due to the excellent price, good quality and beautiful appearance of these pens, they sold out quickly. When checking out, the salesperson found that the total sales amount of these pens was (399a + 805) yuan, Based on the above information, can you find out the total number of pens purchased at the stationery counter and the purchase price of each pen?
( ⊙o⊙


If x pens are purchased, they are:
399a+805=aX+2X,
X=(399a+805)/(a+2)=[399(a+2)+7]/(a+2)=(399+7/(a+2)
Because a is an integer and X is an integer, a = 5,
X = 400



A mobile communication company has set up two kinds of communication services, "global link": the user pays 50 yuan monthly rent first, and then pays 0.4 yuan for each minute of the call; "Express link": no monthly rent is paid. For each minute of the call, the user pays 0.6 yuan (1) how many minutes of the call in a month, The cost of two kinds of mobile communication is equal. (2) which is the best way for someone to estimate the cost of one month and 300 minutes. (3) write the relationship between y1.y2 and X


1. Set up a call for X minutes
50+0.4x=0.6x
0.2x=50
x=250
2. The first way: 50 + 0.4 × 300 = 50 + 120 = 170
The second way: 0.6 × 300 = 180
The first way is cost-effective
3、y1=50+0.4x
y2=0.6x



If the area of the diamond ABCD is 24 square centimeters, and the diagonal AC ratio BD is 1:3, what is the side length of the diamond


In this way, let AC = x, BD = y, according to the area of the diamond is 24, we get 0.5 × x × y = 24 ①, the diagonal AC is 1:3, so y = 3x ② according to the two formulas of ① and ②, we get x = 2 √ 2, y = 6 √ 2, because the diagonals of the diamond are perpendicular to each other and equally divided, so the side length = √ [(0.5x)? + (0.5y)?] = √ (2 + 18) = 2 √ 5



Solve the equation (the square of x-6x-2 = 0)


The square of x-6x-2 = 0
x^2-6x=2
(x-3)^2=2+3^2
(x-3)^2=11
X-3 = positive and negative root sign 11
X1 = radical 11 + 3 x2 = - radical 11 + 3



A and B vehicles leave from ab at the same time and meet at 6km away from the midpoint. It is known that the speed of a vehicle is five sixths of that of B vehicle. How many meters is ab away
The other people's answer is 6 times 2. Who can explain why to me


When you draw a line diagram, you can see at a glance: 6 × 2 = 12 km, which means that the express train runs more than the local train. The express train runs 6 / 11 of the whole journey, while the local train runs 5 / 11, with a difference of 6 / 11-5 / 11 = 1 / 11
So 12 △ 1 / 11 = 132 km
Do you understand?
There are also simple calculations:
6÷(6/11-1/2)
=6÷1/12
=132 km



It is known that the circumference of isosceles triangle is 16cm, one side is 5cm long, and the other two sides are equal to several


5cm is the bottom time
The other two sides are equal to: (16-5) △ 2 = 5.5cm
5 cm is waist time
Bottom = 16-5 × 2 = 6cm



If a, B and C are three arbitrary integers, how many integers will there be among a + B2, B + C2 and C + A2? Please use the parity of integers to explain the reason


There will be at least one integer. According to the parity of integers, three cases can be determined: odd + even = odd, if divided by 2, it is not equal to the integer. Odd + odd = even, if divided by 2, it is equal to the integer. Even + even = even, if divided by 2, it is equal to the integer Four cases: all odd numbers: then a + B divided by 2, B + C divided by 2, C + a divided by 2, all integers are even numbers: then a + B divided by 2, B + C divided by 2, C + a divided by 2, all integers are odd and even numbers: then a + B divided by 2, B + C divided by 2, C + a divided by 2, an integer is even and odd numbers: then a + B divided by 2, B + C divided by 2, C + a divided by 2, an integer is odd and even numbers



Practical problems of tree planting
There is a road with a length of 2000 meters. A lamp post is buried 50 meters apart on both sides of the road. How many lamp posts do you need to buy from the beginning to the end?


Because 2000 / 50 = 40
So from the beginning to the end, we need to bury street lamp poles = 40 + 1 = 41