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Zhuangzhuang and some children went to the fast food restaurant for dinner. They bought 10 hamburgers and French fries, which cost 80 yuan. How many hamburgers and French fries did they buy? You can do it in any way, but don't use the equation with y French fries 5 yuan hamburger 12.5 yuan
Your question is short of conditions. Please add the unit price of hamburger and French fries,
If it's all hamburgers, it costs 12.5 × 10 = 125 yuan
Obviously not,
Number of French fries
=(125-80) / (12.5-5) = 45 / 7.5 = 6 portions
Hamburgers = 10-6 = 4
(9x10 negative third power) x (- one third X10 negative fourth power)
=-The negative 7th power of 9x1 / 3x10
=-The negative 7th power of 3x10
There is a road between a and B. Li Ming starts from a and walks to B, while Zhang Ping starts from B and rides a motorcycle to A. After 80 minutes, the two meet on the way. Zhang Ping turns back to B immediately after arriving at a, and after 20 minutes after the first meeting, Zhang Ping catches up with Li Ming on the way. Zhang Ping turns back to a immediately after arriving at B, and so on How many times did Zhang Ping catch up with Li Ming when he reached the second place?
The line diagram is as follows: suppose Li Ming walked x kilometers from the first meeting to the first time Zhang Ping caught up with Li Ming, then Zhang Ping walked x (80 ／ 20) × 2 + x = 9x (kilometers) in the same time, that is, Zhang Ping's speed was 9x ／ x = 9 (Times) of Li Ming's speed in the same time. That is to say, when Li Ming walked from the first place to the second place, Zhang Ping rode a motorcycle for 9 whole journey Among them, there are 5 whole journey from land B to land a, and 4 whole journey from land a to land B. every whole journey from land a to land B, Zhang Ping must catch up with Li Ming once. Therefore, Zhang Ping has caught up with Li Ming four times. A: Zhang Ping has caught up with Li Ming four times
(2005 + 1 / 2003) × 1 / 2004 simple algorithm, to explain how to calculate!
It is (2005 + 1 / 2003) × 1 / 2004 = (2004 + ---) × 1 / 2004=
(2005+1/2003)×1/2004=（2004+--2004/2003-------）×1/2004=1+1/2003=2004/2003
Have a good time
A and B drive from a to B at the same time. After 5 hours, a arrives at B. A travels 80 kilometers per hour, B 70 kilometers per hour
How many kilometers is car B away from ground B when it arrives?
Distance from a to B = 80 × 5 = 400 km
Car B runs 70 × 5 = 350 km
Car B is 400-350 km away from ground B
(2x-3y)^3 (2a^2+3b^3)^3
It's a process
(2x-3y)^3
=8x^3-12x^2y+18xy^2-27y^3
(2a^2+3b^3)^3
=8a^6+12a^4b^3+18a^2b^6+27b^9
A and B two vehicles respectively from AB two places at the same time relative to each other after 3 hours from the midpoint of 36 kilometers meet, known a, B, two vehicle speed ratio is 3:2, find AB two places how many kilometers away
Suppose the speed of car a is 3, then the speed of car B is 2V
3vx3-2vx3=36x2
The solution is v = 24
Then the distance between the two places is: 3vx3 + 2vx3 = 15V = 15x24 = 360km
The decimal point of a decimal is moved one place to the left, and the number obtained is 2.52 less than the original number. This decimal is______ ．
2.52 ÷ (1-110), = 2.52 ÷ 910, = 2.8; answer: the decimal is 2.8, so the answer is: 2.8
A. B is 460 km away from the two places. Two hours after train a departs from a, train B departs from B and meets train a in four hours. It is known that train a travels 10 km more per hour than train B. how many kilometers does train a travel per hour on average?
Let car a travel x kilometers per hour, then car B travel X-10 kilometers per hour. The equation is: 2x + (X-10 + x) × 4 = 460 & nbsp; 2x + (2x-10) × 4 = 460, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2x + 8x-40 = 460, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp
Given the function f (x) = sin (2x - π / 3), X ∈ [0, π], and the equation f (x) = m has two unequal real roots
① Find the value range of M. 2 find the sum of two equations
x∈[0,π]
2x-π/3∈[-π/3,5π/3]
f(x)=m=sin(2x-π/3)
(1)m∈[-1,1]
(2) When m ≥ 0, the sum of the two equations is π
When - 1
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